Answer:
1
Step-by-step explanation:
Angles that create a triangle always add up to 180.
To find sides that create triangles, we have to use the Triangle Inequality Theorem.
It's where side A + B will <em>always</em> be greater than side C
and B + C will always be greater than side A
<em>and</em> A + C will always be greater than side B.
So let's check all of these answers and pick the one that's incorrect.
A.
10 + 25 + 145 = 180?
Correct!
B.
9 + 15 > 9?
Correct!
15 + 9 > 9?
Correct!
9 + 9 > 15?
Correct!
C.
40 + 70 + 60 = 180?
Incorrect! 40 + 70 + 60 = 175 which is less than 180.
The answer is three angles measuring 40 m, 70 m, and 60 m.
Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
To solve this problem you must apply the procceddure shown below:
1. You have the following system of equations:
<span>
x+y = 3
2x–y = 6
2. Then, you must clear the variable y from the first equation and susbtitute it into the second equation, as below:
x+y=3
y=3-x
2x-y=6
2x-(3-x)=6
2x-3+x=6
3x=6+3
3x=9
3. Therefore, the value of x is:
x=9/3
x=3
4. As you can see, the correct answer is:
x=9
</span>
Answer:
y = 18
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
y = 2x + 12
x = 3
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: y = 2(3) + 12
- Multiply: y = 6 + 12
- Add: y = 18
Slant height of tetrahedron is=6.53cm
Volume of the tetrahedron is=60.35
Given:
Length of each edge a=8cm
To find:
Slant height and volume of the tetrahedron
<u>Step by Step Explanation:
</u>
Solution;
Formula for calculating slant height is given as
Slant height=
Where a= length of each edge
Slant height=
=
=
=6.53cm
Similarly formula used for calculating volume is given as
Volume of the tetrahedron=
Substitute the value of a in above equation we get
Volume=
=
=
Volume=
=60.35
Result:
Thus the slant height and volume of tetrahedron are 6.53cm and 60.35
