Question

Oula is going on an outdoor expedition with his family. The expedition will include a hunting event, a fishing event, a hiking event, and a camping event. There are 4 hunting, 7 fishing, 6 hiking, and 3 camping events for Oula's family to choose from.

Answer 1

We can have 504 difference outdoor expeditions possible.

Step-by-step explanation:

We have , Oula is going on an outdoor expedition with his family. The expedition will include a hunting event, a fishing event, a hiking event, and a camping event. There are 4 hunting, 7 fishing, 6 hiking, and 3 camping events for Oula's family to choose from. We need to find how many difference outdoor expeditions possible. Let's find out:

According to question , Number of events are

$Hunting=4\\Fishing=7\\Hiking=6\\Camping=3$

We can solve problems like this using multiplication rules. Since the order of events in the expedition does not matter, we can multiply all numerical values in any order we so choose.  

⇒ $4(7)(6)(3)$

⇒ $504$

Therefore , We can have 504 difference outdoor expeditions possible.