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Likurg_2 [28]
2 years ago
7

I’ll award brainliest! no links

Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
7 0
YZ=8.66 see pic for work

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A. 0<br><br><br> B. 1<br><br><br> C. 2<br><br><br> D. 3
zloy xaker [14]
-19 to -15 would be a positive 4 difference

19 to 15 = 4 this would be a -4 difference

3 to 7 is a positive 4 difference

-3 to 7 is a difference of 10

so there is 1 with a -4 difference
 answer is B.


6 0
2 years ago
Question number 8. Prove that 3 + √5 is an irrational number.​
Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

\\  \sf \: 3 +  \sqrt{5}  =  \frac{a}{b}   \\  \\   \qquad \: \tiny \sf{(where \:  \: a \:  \: and \:  \: b \:  \: are \:  \: integers \:  \: and \:  \: b \:  \neq \: 0)} \\

\\  \sf \:  \sqrt{5}  =  \frac{a}{b}  - 3 =  \frac{a - 3b}{b}  \\

Since, a, b and 3 are integers. So,

\\ \sf \:  \frac{p - 3b}{b}  \\  \\  \qquad \tiny \sf{ \: (is \:  \: a \:  \: rational \:  \: number \:) } \\

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

\\

Hence, 3 + √5 is an irrational number.

7 0
3 years ago
Math 2 Of high school
Daniel [21]

Answer:

  • B. BC = 18 so ∆ABC ~ ∆DEF by SAS

Step-by-step explanation:

\bf \cfrac{AB}{DE}  =  \cfrac{BC}{EF}

  • \bf \cfrac{15}{10}  =  \cfrac{BC}{12}
  • \bf  \cfrac{3}{2}  =  \cfrac{BC}{12}
  • \bf BC =  \cfrac{3}{2}  \times 12
  • \bf 3 \times 6
  • \bf BC = 18
  • \bf \angle B = \angle \: E

So, ∆ABC ~ ∆DEF by SAS.

<h3><u>------------------------------------</u></h3>
7 0
2 years ago
There are 18 students on the debate club. How many ways can the club send 4 students to the next debate
olya-2409 [2.1K]

There are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have the total number of students = 18

The number of ways the club send 4 students to the next debate is:

= C(18, 4)

= \rm \dfrac{18!}{4!(18-4)!}

= 3060

Thus, there are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

5 0
2 years ago
Complete the table below.
Drupady [299]

Answer:

A (in millions) B (in millions) C D E F G

Total Market Value Total Shares Issued Value Per Share Amount Invested Charge D minus E Shares Purchased

$47 2 $  

23.50

$4,000 $250 $  

3,750

159.6

$25 4 $  

6.25

$4,000 $250 $  

3,750

600

$31 3 $  

10.33

$4,000 $250 $  

3,750

363

$12 12 $  

1.00

$4,000 $300 $  

3,700

3,700

$90 18 $  

5.00

$4,000 $300 $  

3,700

740

$26 3 $  

8.67

$4,000 $300 $  

3,700

426.8

$84 22 $  

3.82

$4,000 none $  

4,000

1,047.1

$32 5 $  

6.40

$4,000 none $  

4,000

625

$25 3 $  

8.33

$4,000 $275 $  

3,725

447.20

$27 3 $  

9.00

$4,000 $275 $  

3,725

413.9

Step-by-step explanation:

Those are the answers, copy and pastes- good luck though : ))

3 0
2 years ago
Read 2 more answers
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