Answer: So if you had 570 cm of ribbon, then 570%2F8.5=67.05 which means that about 67 students can do the experiment (round down to the nearest whole number).
Explanation: If you had 8.5 cm of ribbon, then only 8.5%2F8.5=1 student can do the experiment. If you had 17 cm of ribbon, then 17%2F8.5=2 students can do the experiment.
The answer is D. Effective collisions lead to chemical reactions!
For this problem, we use the formula for sensible heat which is written below:
Q= mCpΔT
where Q is the energy
Cp is the specific heat capacity
ΔT is the temperature difference
Q = (55.5 g)(<span>0.214 cal/g</span>·°C)(48.6°C- 23°C)
<em>Q = 304.05 cal</em>
It's essentially another word for concentration, of the acid. e.g. "the molarity of the acid is 3moldm^-3"
Answer:
Explanation:
= Initial Concentration of KCl = 2.7 M
= Volume of KCl = 1 M
= Final concentration of KCl = 1 M
= Amount of water
We have the relation
The amount of water that is to be added is 
.
