The variance is the total of the squared distances of the given data from the mean.
This can be calculated through the equation,
σ² = summation of X² / N - μ²
where σ² is the variance X's are the data, N is the number of terms, and μ is the mean.
summation of X² = 100² + 100² + 120² + 120² + 180² = 81200
N = 5
μ = (100 + 100 + 120 + 120 + 180) / 5
μ = 124
Substituting these values to the equation for variance,
σ² = (81200/5) - 124² = 864
Thus, the variance is equal to 864.
Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
Answer:
250 of 65% acid
100 gallons of 30% acid
Really sorry if this is incorrect, I had this question on my Lesson 16 test, and I don't know if it's correct or not...
Answer:
Step-by-step explanation:
3
x
2
+
4
x
+
19
−
f
(
x
)
=
0
Answer:
4. A
5. B
Step-by-step explanation:
4. I'll solve question four first:
The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.
5--3/2--2 or 8/4;simplified to 2/1 or 2.
Now use point-slope form: y-y1 = m(x-x1)
y--3 = 2(x--2): Substitute in the values of y1, m, and x1.
y+3 = 2x + 4: Distribute.
y = 2x + 1: Subtract three from both sides.
5. Do the same for question 5.
The first point is (-4, 2), the second point is (4, -1).
-1-2/4--4; -3/8.
Now use point-slope form:
y-2 = -3/8x -12/8: Substitute in the values of x1, y1, m, and distribute the slope to the parentheses.
y = -3/8x + 1/2
