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3 years ago

9

Ruth walks diagonally from one corner of a square plaza to another .each side of the plaza is 50 meters. What is the diagonal di

stance across the plaza? Round your answer to the nearest tenth of a matter.

1 answer:

jek_recluse [69]3 years ago

3 0

Answer:u tell me

Step-by-step explanation:

You might be interested in

Can some please help me with this math question.

Veseljchak [2.6K]

Answer:

C- Inverse

Step-by-step explanation:

Logarithmic example:

log₆ of 6, the answer is 1.

Exponential example:

$6^{1}$ = 6

These are inverses

hope this helps :)

6 0

2 years ago

Simplified<br> Quickly please

UkoKoshka [18]

Answer:

3a:20d+35

3b:35u+49q+56

4a:15+20t

4b:96k+120t+84

5a:24t+108m+60

5b:56q+28b+35

6a:14q+10w+24

6b:54v+99+27t

7a:16g+24+24c

7b:30a+55+50d

(i think thats what they are but the picture is small so its kind of hard to see)

Step-by-step explanation:

(since theres 10 total ill just give an example on how i solved 5a)

5(4d+7)

simplify into: (5•4d)+(5•7)

multiply: (20d)+(35)

since you do not know what d is, you cannot add them

remove parentheses once done:20d+35

(you don't need parentheses since multiplication come before addition but its easier to just use them)

<h2>Hope this helps</h2>

4 0

2 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

If 6 lemons cost 90p what is the price of 1 lemon and four lemons

alina1380 [7]

75p is the correct answer because 1 lemon is 15p

8 0

3 years ago

Read 2 more answers

12-2(n-1)=-18<br><br> aa help plzz

Luda [366]

Answer:

n=16

Step-by-step explanation:

Let's solve your equation step-by-step.

12−2(n−1)=−18

Step 1: Simplify both sides of the equation.

12−2(n−1)=−18

12+(−2)(n)+(−2)(−1)=−18(Distribute)

12+−2n+2=−18

(−2n)+(12+2)=−18(Combine Like Terms)

−2n+14=−18

−2n+14=−18

Step 2: Subtract 14 from both sides.

−2n+14−14=−18−14

−2n=−32

Step 3: Divide both sides by -2.

−2n /−2 = −32 /−2

n=16

8 0

2 years ago