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pashok25 [27]
3 years ago
9

Ln (5 divided by three)

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

ln  ( − 15 d^3  v e by )

Step-by-step explanation:

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QveST [7]

Answer:

y54678

Step-by-step explanation:

vggndndhhcbcbfhfnnf

8 0
3 years ago
Samuel deposits $1,800 in an account that earns 12% simple annual interest. How many months will it take for Samuel's account ba
Artemon [7]
In order to use the simple interest formula, we first define the variables. The interest would be equal to Samuel's desired amount $ 2,488 minus the principal amount of $ 1,800 which is then equal to $ 688. The rate must be in decimal form which is equal to 0.12 while t is expressed in years. Substituting the values, t is equal to 3. Thus, it will take 36 <span>months for Samuel's account balance to reach $2,448. </span>
6 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
Will give brainliest if you get this right!
SSSSS [86.1K]

The answer is x=6. I double checked the work and am 100% sure thats the answer

7 0
3 years ago
Read 2 more answers
Round tables seating 8 people and rectangular tables seating 12 people are being used at a banquet for 8th graders. The ratio of
Tamiku [17]

Answer:

<u>36 tables are used to seat  the students at the banquet: 12 rectangular and 24 round.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Round tables = 8 seats

Rectangular tables = 12 seats

Ratio of round tables to rectangular tables = 2:1

Number of students = 336

2. How many tables are used to seat 336 students at the banquet, if no table has an empty seat?

x = Number of rectangular tables

2x = Number of round tables

Let's solve for x, using this equation:

12x + 8 (2x) = 336

12x + 16x = 336

28x = 336

x = 336/28

x = 12 ⇒ 2x = 24

12 + 24 = 36

<u>36 tables are used to seat  the students at the banquet: 12 rectangular and 24 round.</u>

6 0
3 years ago
Read 2 more answers
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