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sergij07 [2.7K]

3 years ago

11

Renewable resources include wind energy, solar energy, wood, and plant materials. Which statement best describes renewable resou

rces? man-made materials that replenish over time natural resources that replenish themselves over time natural resources that have a limited supply man-made materials that have a limited supply

1 answer:

svetlana [45]3 years ago

7 0

Answer: B

Explanation:

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Who has greater displacement, an astronaut who has just completed an orbit of the earth or you when you have just traveled from

Arte-miy333 [17]

Answer:

Explanation:

This is going to sound like an absurd answer, but sometimes physics can be a little strange.

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3 years ago

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GaryK [48]

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3 years ago

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A car is stationary. It accelerates at 0.8 ms^2 for 10 s and then at 0.4 ms^2 for a further 10 s. Use the equations of motion to

pav-90 [236]

Answer:

The final displacement of the car is 140 meters.

Explanation:

The final displacement of the car ( $s$ ), in meters, is the sum of the change in displacement associated with each part of the journey, which is derived from the following kinematic formulas:

$s = s_{1} + s_{2}$ (1)

$s_{1} = \frac{1}{2}\cdot a_{1}\cdot t_{1}^{2}$ (2)

$v_{o,2} = a_{1}\cdot t_{1}$ (3)

$s_{2} = v_{o,2} + \frac{1}{2}\cdot a_{2}\cdot t_{2}^{2}$ (4)

Where:

$s_{1}$ - Traveled distance of the first part, in meters.

$s_{2}$ - Traveled distance of the second part, in meters.

$a_{1}$ - Acceleration in the first part, in meters per square second.

$a_{2}$ - Acceleration in the second part, in meters per square second.

$v_{o,2}$ - Initial speed of the car in the second part, in meters per second.

$t_{1}$ - Time taken in the first part, in seconds.

$t_{2}$ - Time taken in the second part, in seconds.

If we know that $a_{1} = 0.8\,\frac{m}{s^{2}}$ , $t_{1} = 10\,s$ , $a_{2} = 0.4\,\frac{m}{s^{2}}$ and $t_{2} = 10\,s$ , then the distance traveled by the car is:

By (2):

$s_{1} = \frac{1}{2}\cdot \left(0.8\,\frac{m}{s^{2}} \right)\cdot(10\,s)^{2}$

$s_{1} = 40\,m$

By (3):

$v_{o,2} = \left(0.8\,\frac{m}{s^{2}} \right)\cdot (10\,s)$

$v_{o,2} = 8\,\frac{m}{s}$

By (4):

$s_{2} = \left(8\,\frac{m}{s} \right)\cdot (10\,s) + \frac{1}{2}\cdot \left(0.4\,\frac{m}{s^{2}} \right)\cdot (10\,s)^{2}$

$s_{2} = 100\,m$

By (1):

$s = 140\,m$

The final displacement of the car is 140 meters.

5 0

3 years ago