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Diano4ka-milaya [45]
3 years ago
8

QUIK!!!!!!!!!!!!! 1. Compare your scores to your partner’s scores. Explain the reason for any differences. 2. How can improving

your balance and coordination affect your performance in sports or recreational activities? 3. What activity was the most difficult for you to perform? Why? 4. Describe an activity that could help improve your striking and your reaction time skills. 5. Select a physical activity or sport that you have never done but would like to try one day. Identify at least one element of skill-related fitness that is important to being successful in this activity. 6. What power-increasing activities do you need to perform regularly to improve your performance
Physics
1 answer:
kvv77 [185]3 years ago
6 0
2.Improving my balance and coordination can affect my performance in sports or recreational activities by planing better in activities also <span>improving my speed. My activities all need skills that I am really good at.
3.</span>The activity that was most difficult for me to perform was the Stork Stance test because I am not good with balancing and that is something <span>I need to improve.
4.</span>An activity that could help improve my striking and my reaction time.
5.One sport that I have never done but that I would like to try one day is <span>baseball.
</span>One element of skill-related fitness that is important to being successful in the activity is speed and reaction time skills.6. R<span>unning, jogging, sprinting, and jump roping.</span>
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Answer:

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Explanation:

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What do wind turbines, hydroelectric dams, and ethanol plants have in common
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Four charges with equal magnitudes of 10.6 × 10-12 C are placed at the corners of a rectangle. The lengths of the sides of the r
cricket20 [7]

Answer:

Figure a. E_net = 99.518 N/C

Figure b. E_net = 177.151 N / C

Explanation:

Given:

- Attachment for figures missing in the question.

- The dimensions for rectangle are = 7.79 x 3.99 cm

- All four charges have equal magnitude Q = 10.6*10^-12 C

Find:

Find the magnitude of the electric field at the center of the rectangle in Figures a and b.

Solution:

- The Electric field generated by an charged particle Q at a distance r is given by:

                                         E = k*Q / r^2

- Where, k is the coulomb's constant = 8.99 * 10^9

Part a)

- First we see that the charges +Q_1 and +Q_3 produce and electric field equal but opposite in nature. So the sum of Electric fields:

                                 E_1 + E_3 = 0

- For Charges -Q_2 and +Q_4, they are equal in nature but act in the same direction towards the negative charge -Q_2. Hence, the net Electric Field at center of the rectangle can be given as:

                                  E_net = E_2 + E_4

                                  E_2 = E_4

                                  E_net = 2*E = 2*k*Q / r^2

- The distance r from each corner to mid-point of the rectangle is constant. It can be evaluated by Pythagoras Theorem as follows:

                                  r = sqrt ( (7.79/200)^2 + (3.99/200)^2 )

                                  r = sqrt ( 1.9151*10^-3 ) = 0.043762 m

- Plug the values in the E_net expression developed above:

                                  E_net = 2*(8.99*10^9)*(10.6*10^-12) / 1.9151*10^-3

                                 E_net = 99.518 N/C

Part b)

- Similarly for Figure b, for Charges -Q_2 and +Q_4, they are equal in nature but act in the same direction towards the negative charge -Q_2. Also, Charges -Q_1 and +Q_3, they are equal in nature but act in the same direction towards the negative charge -Q_1. These Electric fields are equal in magnitude to what we calculated in part a).

- To find the vector sum of two Electric Fields E_1,3 and E_2,4 we see the horizontal components of each cancels each other out. While the vertical components E_1,3 and E_2,4 are equal in magnitude and direction.

Hence,

                                  E_net = 2*E_part(a)*cos(Q)

- Where, Q is the angle between resultant, vertical in direction, and each of the electric field. We can calculate Q using trigonometry as follows:

                                  Q = arctan ( 3.99 / 7.79 ) = 27.12 degrees.

- Now, compute the net electric field E_net:

                                  E_net = 2*(99.518)*cos(27.12)

                                  E_net = 177.151 N / C

               

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The waves that occur when you drop and stone into the water when skipping rocks
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3 years ago
a baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 12 Kg. how much energy does
Tcecarenko [31]

Answer:

The carriage has the energy, W = 2469.6 J

Explanation:

Given data,

The height of the hill, h = 21 m

The carriage with the baby weighs, m = 12 kg

The energy possessed by the body due to its position is the potential energy,

                                      <em>W = P.E = mgh joules</em>

Substituting the values,

                                       W = 12 x 9.8 x 21

                                            = 2469.6 J

Hence, the carriage has the energy, W = 2469.6 J

8 0
3 years ago
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