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Bumek [7]
3 years ago
15

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the product of the pressure and the volume

remains constant: PV = C. (a) Find the rate of change of volume with respect to pressure. dV dP = (b) A sample of gas is in a container at low pressure and is steadily compressed at constant temperature for 13 minutes. Is the volume decreasing more rapidly at the beginning or the end of the 13 minutes? Explain. From the formula for dV dP , we see that as P increases, the absolute value of dV dP . Thus, the volume is more rapidly at the beginning. (c) Write the formula for isothermal compressibility (see this example) in terms of P. β =
Physics
1 answer:
11111nata11111 [884]3 years ago
4 0
I’m stuck on this too
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The lowest note on a grand piano has a frequency of 27.5 Hz. The entire string is 2.00 m long and has a mass of 400 g. The vibra
Norma-Jean [14]

Answer:

1456 N

Explanation:

Given that

Frequency of the piano, f = 27.5 Hz

Entire length of the string, l = 2 m

Mass of the piano, m = 400 g

Length of the vibrating section of the string, L = 1.9 m

Tension needed, T = ?

The formula for the tension is represented as

T = 4mL²f²/ l, where

T = tension

m = mass

L = length of vibrating part

F = frequency

l = length of the whole part

If we substitute and apply the values we have Fri. The question, we would have

T = (4 * 0.4 * 1.9² * 27.5²) / 2

T = 4368.1 / 2

T = 1456 N

Thus, we could conclude that the tension needed to tune the string properly is 1456 N

4 0
3 years ago
What is the wavelength of a wave?
Sunny_sXe [5.5K]
The wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.
6 0
3 years ago
A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the s
yan [13]

Answer:

The  force is F_1  = 400.8 \  N

Explanation:

From the question we are told that

   The first  diameter is  d_1 =  4.0 \ cm =  0.04 \ m

   The second diameter is  d_2  =  8.0 \ cm  = 0.08 \  m

   

Generally the first area is  

         A_1  =  \pi  * \frac{d^2_1 }{4}

=>      A_1  = 3.142  * \frac{0.04^2}{4}

=>       A_1  =  0.00126 \ m^2

The  second area is  

     A_2 =  \pi  * \frac{d^2_2 }{4}

     A_2  = 3.142  * \frac{0.08^2}{4}

     A_2  =  0.00503 \ m^2

For a hydraulic press the pressure at both end must be equal .

Generally  pressure is mathematically represented as

    P =  \frac{F}{A}

=>  

   \frac{F_1}{A_1 }  =  \frac{F_2}{A_2 }

=>   F_1  =  \frac{1600}{0.00503}  *  0.00126

=>    F_1  = 400.8 \  N

8 0
3 years ago
Explain the following (using the concepts of moment, center of gravity and stability.) a) Racing cars are low, with wide wheels.
LUCKY_DIMON [66]

Answer:

b

Explanation:

3 0
3 years ago
A particle undergoes two displacements. The first has a
Novay_Z [31]
First you need to draw the picture of the problem to better understand it. Like the one bellow. 

In this task you have 2 sides of triangle and we can calculate angle between them. Angle between them is 120 - 35 = 85 degrees.

Once you have those 3 variables you can calculate third side of triangle using cosine law.
a - second displacement
b - first displacement
c- resultant displacement.

a^{2} =  b^{2}+ c^{2}-2*b*c*cos85
now we just need to calculate this.
a^{2} = 38439.458
a = 196

now, we use cosine law again to find the angle between second and first displacement.
\alpha = 45.36 degrees

The angle marked with "?" in the graph is our direction angle. We will call it \beta

\beta =90-30-45.36 = 14.64

Second displacement has magnitude of 196 and a direction of -14.64 with positive x axis
3 0
3 years ago
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