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FromTheMoon [43]
4 years ago
10

A pail holds

Mathematics
1 answer:
OLga [1]4 years ago
8 0
There are 16 cups in a gallon. If there are 414 gallons,
414 x 16 = 6,624
Then the pail can hold 6,624 cups of water! :)
You might be interested in
Find the difference and simplify the following<br> expressions.<br> (n – 8) – (2n + 2)
blagie [28]

Answer:

-n-10

Step-by-step explanation:

(n-8)-(2n+2)

n-8-(2n+2)

n-8-2n-2

-n-8-2

-n-10

4 0
3 years ago
I have a venn diagram the two sections are multiples of 4 and the other on is even numbers but I don't know what to put in it??
stira [4]
You can always use mathway to help
5 0
3 years ago
HELP PLEASE!!! WILL GIVE THANKS &amp; BRAINLIEST
zhuklara [117]

The graph that best represents the system of inequalities would be the second one.

y > -2x - 2

y \leq x + 4

7 0
3 years ago
Someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi. We think the
denpristay [2]

Answer:

The sample size must be greater than 37 if we want to reject the null hypothesis.

Step-by-step explanation:

We are given that someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi.

Also, we are given a level of significance of 5%.

Let \mu = <u><em>mean breaking strength of their climbing rope</em></u>

SO, Null Hypothesis, H_0 : \mu = 2,000 psi       {means that the mean breaking strength of their climbing rope is 2,000 psi}

Alternate Hypothesis, H_A : \mu < 2,000 psi      {means that the mean breaking strength of their climbing rope is lower than 2,000 psi}

Now, the test statistics that we will use here is One-sample z-test statistics as we know about population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = ample mean strength = 1,997.2956 psi

            \sigma = population standard devaition = 10 psi

            n = sample size

Now, at the 5% level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

So, to reject our null hypothesis our test statistics must be less than -1.645 as only then we have sufficient evidence to reject our null hypothesis.

SO,  T.S. < -1.645   {then reject null hypothesis}

         \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < -1.645

         \frac{1,997.2956-2,000}{\frac{10}{\sqrt{n} } } < -1.645

         (\frac{1,997.2956-2,000}{10}) \times {\sqrt{n} } } < -1.645

          -0.27044 \times \sqrt{n}< -1.645

               \sqrt{n}> \frac{-1.645}{-0.27044}

                 \sqrt{n}>6.083

                  n > 36.99 ≈ 37.

SO, the sample size must be greater than 37 if we want to reject the null hypothesis.

7 0
4 years ago
Suppose that 9 green balls and 14 purple balls are placed in an urn.  Two balls are then drawn in succession.  What is the proba
Hitman42 [59]
<span>14/23, or approximately 60.87% Since the first ball is replaced before the second is drawn, the two events are independent. And the probability of the second ball being purple is the percentage of the balls that are purple in the urn. The total number of balls is 9+14 = 23 and 14 of those balls are purple, so 14/23 = probability of the second ball drawn being purple. It's approximately 0.608695652, or 60.87%</span>
8 0
4 years ago
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