Answer:
4Na + O₂ → 2Na₂O
6.82g
Explanation:
The combustion of sodium involves combining the element with oxygen gas:
4Na + O₂ → 2Na₂O
We have been given 5g of Na.
The balanced reaction equation is given as shown above. This reaction is also a synthesis or combination reaction.
b. Maximum amount of product that can be obtained.
Sodium is the limiting reactant and it will determine the amount of product that can be formed.
To solve this, we find the number of moles of the given sodium.
Mass of given sodium = 5g
Molar mass of Na = 23g/mol
Number of moles of Na =
Insert the parameters and solve;
Number of moles of Na = = 0.217moles
From the balanced reaction equation:
4 moles of Na will produce 2 moles of Na₂O
0.217 moles of Na will produce = 0.11mole of Na₂O
So;
Mass of Na₂O = number of moles x molar mass
Molar mass of Na₂O = 2(23) + 16 = 62g/mol
Mass of Na₂O = 0.11 x 62 = 6.82g
First you need to know the value of Kp for this reaction. The reaction is: SO2 (g) + 2 H2S (g)<=> 3S(s) + 2 H2O(g): Kp = PH2O^2 / PSO2(PH2O)^2 but since the problem is lacking in details.
Otherwise, let x = PSO2 = PH2S. Then:
Kp = (22/760 atm)^2 / x^3
x = cube root (0.289)/Kp = PSO2
But if the kp is given, let us assume it is 8.0*10^15The solution would be:convert the given pressure of water to atm, which is: 0.029
Kp=P(H2O)^2/P(SO2)P(H2S)^2
8.0*10^15 = (0.029)^2/x^3
(8.0*10^15).(x^3)=8.41*10^-4
take the cube root of both sides(2.0*10^5).x = 9.439130*10^-2x = P (SO2) = 4.6*10^-7
Answer:
For 12.8 g there 0.807 × 10³ formula units.
Explanation:
Given data:
Mass of MgCl₂ = 12.8 g
Formula units for given mass = ?
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/molar masss
Number of moles = 12.8 g/ 95.211 g/mol
Number of moles = 0.134 mol
According to the Avogadro number,
one moles = 6.022 × 10³ formula units
For 0.134 mol,
0.134 × 6.022 × 10³ formula units
0.807 × 10³ formula units
For 12.8 g there 0.807 × 10³ formula units.
Answer:
The element with electron configuration 1s² 2s² 2p⁶ will most likely not........
Explanation: