How do u calculate volume

The smaller radius is primarily a result of the magnesium atom having ??

Aleksandr [31]

Answer:

A larger nuclear charge :)

Explanation:

8 0

3 years ago

explain how a metal with one valence electron compares with a metal with more than one valence electron

slamgirl [31]

Explanation:

A metal with one valence electron is highly reactive compared to those with more than one electron.

Atoms including those of metals reacts in order attain a stable electronic configuration just like those of noble gases.

An atom with one valence electron have just one electron in its valence shell.

Metals generally have large sizes.
when the electron in this shell is lost, the metal atom can then attain stability.
therefore, such atom will quickly want to combine with any other willing to accept the electron so that they can be stable.
Those with more than one electron will find it difficult to lose them.
It requires huge energy to remove such electrons compared to the ones with only one valence electron.

learn more:

Valence electrons brainly.com/question/3023499

#learnwithBrainly

7 0

3 years ago

Which of the following lists contain only elements?

N76 [4]

In which elements are belonging to? I will grant that option B ; ti's the best answer.
In which thou might contain the elements zinc , gold , aluminium , and last by not least oxygen.

I truly hope ti's answer helps thou.

7 0

3 years ago

Covert to scientific notation.

gtnhenbr [62]

Answer:

19) 3.6920 × 10⁻⁵

20) 4.059× 10²

21) 2.46810121416 × 10³

22) 1.0000× 10⁻³

Explanation:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

For example:

0.000036920

In scientific notation = 3.6920 × 10⁻⁵

405.9

In scientific notation = 4.059× 10²

2468.10121416

In scientific notation = 2.46810121416 × 10³

0.0010000

In scientific notation = 1.0000× 10⁻³

8 0

3 years ago

First-order reaction that results in the destruction of a pollutant has a rate constant of 0.l/day. (a) how many days will it ta

Klio2033 [76]

Rate equation for first order reaction is as follows:

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}$

Here, k is rate constant of the reaction, t is time of the reaction, $A_{0}$ is initial concentration and $A_{t}$ is concentration at time t.

The rate constant of the reaction is $0.1 day^{-1}$ .

(a) Let the initial concentration be 100, If 90% of the chemical is destroyed, the chemical present at time t will be 100-90=10, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{10}=23.03 days$

Thus, time required to destroy 90% of the chemical is 23.03 days.

(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{1}=46.06 days$

Thus, time required to destroy 99% of the chemical is 46.06 days.

(c) Let the initial concentration be 100, If 99.9% of the chemical is destroyed, the chemical present at time t will be 100-99.9=0.1, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{0.1}=69.09 days$

Thus, time required to destroy 99.9% of the chemical is 69.09 days.

5 0

3 years ago