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IrinaVladis [17]
3 years ago
11

When hot lava reaches seawater, the salts in the water react with the steam to form gaseous hydrochloride acid. You are given a

unbalanced chemical equation for one such reaction and the volume of HCI(g) produced. Explain how you would find the mass of solid sea salt needed to produce the given gas volume.
Chemistry
1 answer:
iren [92.7K]3 years ago
3 0
NaCl + H2O = HCl + NaOH 
FIRST write the equation and balance the equation THEN convert the volume of the gas to moles of the gas PV=nRT THEN according to the stoichiometry of the reaction one mol of gas is produced by one mol of salt. Convert the mol of gas to mol of salt FINALLY calculate the molar mass of the salt and convert the mol of salt to g of salt (m= nxMM)

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Explain why the first ionisation energy of krypton is greater then the first ionisation energy of bromine
MrMuchimi

Answer:

Kr has one more electron than br and so, the nuclear charge increase, which means the nuclear attraction between the nucleus and outer most electron will increase and so will be harder to remove the electron from Kr than Br, so Kr has higher 1st ionisation.

Mark me brainliest!

God bless!

3 0
3 years ago
Insulators prevent the loss of heat. A company is designing a mug that will keep coffee warm for a long time. Which one of these
Mumz [18]
Rubber, because it doesn’t conduct heat and it is a good insulator
3 0
2 years ago
onsider the following reaction: CaCN2 + 3 H2O → CaCO3 + 2 NH3 105.0 g CaCN2 and 78.0 g H2O are reacted. Assuming 100% efficiency
mestny [16]

Answer : The excess reactant is, H_2O

The leftover amount of excess reagent is, 7.2 grams.

Solution : Given,

Mass of CaCN_2 = 105.0 g

Mass of H_2O = 78.0 g

Molar mass of CaCN_2 = 80.11 g/mole

Molar mass of H_2O = 18 g/mole

Molar mass of CaCO_3 = 100.09 g/mole

First we have to calculate the moles of CaCN_2 and H_2O.

\text{ Moles of }CaCN_2=\frac{\text{ Mass of }CaCN_2}{\text{ Molar mass of }CaCN_2}=\frac{105.0g}{80.11g/mole}=1.31moles

\text{ Moles of }H_2O=\frac{\text{ Mass of }H_2O}{\text{ Molar mass of }H_2O}=\frac{78.0g}{18g/mole}=4.33moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3

From the balanced reaction we conclude that

As, 1 mole of CaCN_2 react with 3 mole of H_2O

So, 1.31 moles of CaCN_2 react with 1.31\times 3=3.93 moles of H_2O

From this we conclude that, H_2O is an excess reagent because the given moles are greater than the required moles and CaCN_2 is a limiting reagent and it limits the formation of product.

Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles

Now we have to calculate the mass of excess reactant.

\text{ Mass of excess reactant}=\text{ Moles of excess reactant}\times \text{ Molar mass of excess reactant}(H_2O)

\text{ Mass of excess reactant}=(0.4moles)\times (18g/mole)=7.2g

Thus, the leftover amount of excess reagent is, 7.2 grams.

8 0
4 years ago
Zinc oxide adopts a face-centered cubic arrangement. Both Zinc ions and oxide ions adopt the face-centered cubic arrangement; wi
vichka [17]

Answer:

5.41 ×10⁻²²

Explanation:

We were told right from the question that both the Zinc ions and the Zinc oxide adopts a face-centered cubic arrangement.

Then, the number of ZnO molecule in one unit cell = 4

The standard molar mass of ZnO = 81.38g

Avogadro's constant = 6.023 × 10²³ mole

∴

The mass of one unit cell of zinc oxide can be calculated as:

= \frac{4*81.38}{6.023*10^{23}}

= 5.40461564×10⁻²²

≅ 5.41 ×10⁻²²

∴ The mass of one unit cell of zinc oxide = 5.41 ×10⁻²²

3 0
3 years ago
Are controlled substances and illegal drugs the same thing?
Reil [10]
Well i do think they're the same.
8 0
3 years ago
Read 2 more answers
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