Answer:
Silver
Explanation:
Given parameters:
Mass = 116g
Energy = 511J
Initial temperature = 21.6°C
Final temperature = 40.5°C
Unknown:
Specific heat capacity and the type of metal = ?
Solution:
To solve this problem, we need to find the specific heat capacity of the metal given,
H = m x c x Ф
H is the energy
m is the mass
c is the specific heat capacity
Ф is the change in temperature
511 = 116 x c x (40.5 - 21.6)
511 = 2192.4c
c = 0.233J/g°C
The specific heat capacity of silver is similar to this.
Density = mass/volume
density = 81 grams/0.9 cubic centimetersdensity = 90 grams per cubic centimeter
The density of the sample is 90 grams per cubic centimeter.
Answer:
0.895 g/mL
Explanation:
Step 1: Given data
Mass of liquid Z (m): 2.763 lb
Volume of liquid Z (V): 5.93 cups
Step 2: Convert "m" to grams
We will use the relationship 1 lb = 453.59 g.
Step 3: Convert "V" to milliliters
We will use the relationship 1 cup = 236.59 mL.
Step 4: Calculate the density of the liquid Z
The density (ρ) of the liquid Z is equal to its mass divided by its volume.
The ionic formula of sodium oxide would be Na20
