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vodka [1.7K]
3 years ago
14

Gases with high molecular weights diffuse more slowly than gases with lower molecular weights.

Chemistry
2 answers:
Rom4ik [11]3 years ago
7 0
The answer to this item is TRUE. This can be explained through the Graham's law. This law states that the rate at which gases diffuse is inversely proportional to the square root of their densities which is also related to their molecular masses. 
serg [7]3 years ago
6 0

Answer:

The given statement is true.

Explanation:

Graham's Law:

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molecular mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

  • Higher the molecular mass lower will be effusion rate.
  • Lower the molecular mass higher will be the effusion rate.
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Ca(OH)</span>₂ is <span>strong Bases</span><span>

</span>Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
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