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masha68 [24]
4 years ago
10

As of January 2009, the USA has produced 60,000 metric tons of nuclear waste in 60 yesrs of operating 104 nuclear power plants.

Chemistry
2 answers:
marta [7]4 years ago
8 0
I beleieve its b honey i hope i dont get u wrong :P but sorry if i do 
Ann [662]4 years ago
3 0
B. 83.3 tons p. month
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A sulfur ion has 16 protons and 18 electrons. Find the net charge
andrezito [222]

I think its 2-, it gained 2 electrons.

5 0
4 years ago
Which statement accurately describes differences between RNA and DNA?
Arlecino [84]

Answer:

RNA always folds into a single helix while DNA always folds into a double helix.

<em>I hope this helps you</em>

<em>:)</em>

8 0
2 years ago
Consider the reaction. mc026-1.jpg At equilibrium at 600 K, the concentrations are as follows. [HF] = 5.82 x 10-2 M [H2] = 8.4 x
nadezda [96]

Answer:

2.1 x 10⁻².

Explanation:

  • Generally, the equilibrium constant (Keq) is the product of the concentration of the reaction products divided by the product of the concentration of the reaction reactants, each term is raised to a power equal to its coefficient in the balanced chemical reaction.
  • For the given reaction: 2HF → H₂ + F₂,

Keq = [H₂][F₂] / [HF]²,

Keq = [H₂][F₂] / [HF]² = [8.4 x 10⁻³][8.4 x 10⁻³] / [5.82 x 10⁻²]² = 2.1 x 10⁻².

8 0
3 years ago
A salt contains only barium and one of the halide ions. A 0.158 g sample of the salt was dissolved in water, and an excess of su
Delvig [45]

Answer:

BaBr2

Explanation:

Halide ions are the ions of the elements of group 17 (or 7A), which have 7 electrons in their valence shell, so they need to gain one electron to be stable. If we noted as X the halide, the ion must be X^{-}.

Barium is a metal of group 2 (or 2A) and has 2 electrons in its valence shell, so it must lose these 2 electrons to be stable, and it will form the anion Ba^{2+}. These elements will form an ionic bond, with formula BaX2.

Sulfuric acid has formula H2SO4, and the reaction is:

BaX2 + H2SO4 --> BaSO4 + 2HX

So, for the stoichiometry between BaX2 and BaSO4, and denoting by <em>y</em> the molar mass of the halide, and the molar mass of BaSO4 = 137.33 g of Ba + 32.06 g of S + 4x16 g of O = 233.39

1 mol of BaX2 ------------- 1 mol of BaSO4

(137.33 + 2y) g of BaX2 ------------ 233.39 g of BaSO4

0.158 g of BaX2 --------------------- 0.124 g of BaSO4

By a simple direct three rule:

0.124x(137.33 + 2y) = 0.158x233.39

17.02892 + 0.248y = 36.87562

0.248y = 19.8467

y = 19.8467/0.248

y = 80.03 g/mol

By consulting the periodic table, the halide element that has a molar mass close to 80.03 g/mol is Bromide (Br), which has molar mass 79.9 g/mol. So the salt has formula BaBr2.

8 0
3 years ago
Heat is transferred at a rate of 2 kW from a hot reservoir at 825 K to a cold reservoir at 300 K. Calculate the rate at which th
kakasveta [241]

Answer:

0.004243 KW/K.

Explanation:

From the question given above, the following data were obtained:

Heat transfered (Q) = 2 KW

Temperature of hot reservoir (Tₕ) = 825 K

Temperature of cold reservoir (T꜀) = 300 K

Next, we shall determine the entropy of both reservoir. This can be obtained as follow:

For hot reservoir:

Heat transfered (Q) = 2 KW

Temperature of hot reservoir (Tₕ) = 825 K

Entropy of hot reservoir (Sₕ) =?

Sₕ = Q/Tₕ

Sₕ = 2/825

Sₕ = 0.002424 KW/K

For cold reservoir:

Heat transfered (Q) = 2 KW

Temperature of cold reservoir (T꜀) = 300 K

Entropy of cold reservoir (S꜀) =?

S꜀ = Q/T꜀

S꜀ = 2/300

S꜀ = 0.006667 KW/K

Finally, we shall determine the change in the entropy of the two reservoirs. This can be obtained as follow:

Entropy of hot reservoir (Sₕ) = 0.002424 KW/K

Entropy of cold reservoir (S꜀) = 0.006667 KW/K

Change in entropy (ΔS) =?

ΔS = S꜀ – Sₕ

ΔS = 0.006667 – 0.002424

ΔS = 0.004243 KW/K.

6 0
3 years ago
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