Answer:
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Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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The vertex is (-5, 5) and the parabola opens downward. The vertex form equation is
.. y = -(x +5)^2 +5
B 56
Step-by-step explanation:
Answer:
Step-by-step explanation:
Domain : all real numbers
Range : All real numbers
x - intercept : none
y- intercept : (0,2)
End behavior : Points diagnally to the right
