Question

100 POINTS!!! WILL MARK BRAINIEST!!! What is the maximum number of grams of SO2 that can be fromed when 10.0 g of H2S reacts with 8.5 of oxygen? Given the equation 2H2S + 3O2 --> 2SO2 + 2H2O. PLS SHOW WORK!!

Answer 1

Answer:

Mass = 12.82 g

Explanation:

Given data:

Mass of oxygen = 8.5 g

Mass of H₂S = 10.0 g

Mass of SO₂ = ?

Solution:

Chemical equation;

2H₂S + 3O₂ →  2SO₂ + 2H₂O

Number of moles of H₂S:

Number of moles = mass/ molar mass

Number of moles = 10.0 g / 34 g/mol

Number of moles =0.3 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 8.5 g / 32 g/mol

Number of moles = 0.3 mol

Now we will compare the moles of SO2 with oxygen and hydrogen sulfide.

                         O₂             :         SO₂

                           3             :            2

                           0.3          :            2/3×0.3=0.2 mol

                         H₂S           :            SO₂

                           2              :            2

                         0.3             :           0.3

The number of moles of SO₂  produced by oxygen are less so it will limiting reactant.

Mass of SO₂:

Mass = number of moles × molar mass

Mass = 0.2 mol × 64.1 g/mol

Mass = 12.82 g