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Lostsunrise [7]
2 years ago
9

What could be the fourth quantum number of a 1s^2 electron be?

Chemistry
1 answer:
Bumek [7]2 years ago
6 0

The forth quantum number is Spin quantum number and the value of Spin Quantum Number of 1s² will be +1/2. Therefore, the correct option is (B) option

<h3>What is Spin Quantum Number ?</h3>

It describes the orientation of the electron spin (rotation) in space.

In the given case of 1s² configuration,

since, the Quantum numbers are known as:

  • Principal quantum number (n) which cannot be zero.

       The allowed values of n are therefore 1, 2, 3, 4, and so on.

  • Angular quantum number (l) is able to be any integer between 0  

       and n-1.

       Therefore, for example, If n = 1, l will be 0,

                                                If n = 2, l can be either 0 or 1.

  • Magnetic quantum number (m) is able to be any integer between -l and +l.    

       Therefore, for example, If l = 3, m can be either -3 to +3.

  • Spin Quantum Number (ms): Ms = +½ or -½  accounts for the orientation of the spin axis of an electron as it is able to spin in only one of two directions.

Thus, since the fourth quantum number is Ms, spin, we infer that the answer is (B) option ie, Ms = +1/2 because it represents the positive spin on 1s².

Learn more about Quantum Number Here ;

brainly.com/question/15325270

#SPJ1

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What is the mass of oxygen in 3.34 g of potassium permanganate?
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Answer:

1.35 g

Explanation:

Data Given:

mass of Potassium Permagnate (KMnO₄) = 3.34 g

Mass of Oxygen: ?

Solution:

First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)

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Molar Mass of KMnO₄ = 39 + 55 + 4(16)

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Calculate the mole percent composition of  Oxygen in Potassium Permagnate (KMnO₄).

Mass contributed by Oxygen (O) = 4 (16) = 64 g

Since the percentage of compound is 100

So,

                        Percent of Oxygen (O) = 64 / 158 x 100

                        Percent of Oxygen (O) = 40.5 %

It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.

So,

for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be

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What mass of methane (CH4) gas occupies a volume of 0,462 L at 1atm and 273K
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Explanation:

Since methane gas is at 1 atm and 273 K, it is at standard temperature and pressure(STP).

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0.462 L(0.462 dm^3) at STP of CH4

=(16 g×0.462 dm^3)/22.4 dm^3

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