Explanation:
Cr=35.880/51=0.73≈0.7
P=21.076/31=0.67≈0.7
O=43.543/16=2.71
Divide each by 0.7 u get
Cr=1 ,P =1, O=4
Empirical formula is CrPO4
Answer:
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Answer:
Explanation:
Each coil increases it by a multiple of 100.
=> 50 | 3 | <u><em>15,000</em></u>
=> 100 | 3 | <u><em>30,000</em></u>
=> 150 | 3 | <u><em>45,000</em></u>
Answer:
Mass = 8.46 g
Explanation:
Given data:
Mass of water produced = ?
Mass of glucose = 20 g
Mass of oxygen = 15 g
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂
Number of moles of glucose:
Number of moles = mass/molar mass
Number of moles = 20 g/ 180.16 g/mol
Number of moles = 0.11 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 15 g/ 32 g/mol
Number of moles = 0.47 mol
now we will compare the moles of water with oxygen and glucose.
C₆H₁₂O₆ : H₂O
1 : 6
0.11 : 6/1×0.11 = 0.66
O₂ : H₂O
6 : 6
0.47 : 0.47
Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.
Mass of water produced:
Mass = number of moles × molar mass
Mass = 0.47 mol ×18 g/mol
Mass = 8.46 g
B - two hydrogen atoms and one oxygen atom
