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Rama09 [41]
3 years ago
11

What is the equilibrium constant of pure water at 25°C?

Chemistry
2 answers:
RSB [31]3 years ago
8 0

Answer:

10↑-14

Explanation:

STatiana [176]3 years ago
5 0

Answer: 1.0 × 10-14

Explanation:

Pure water, represented as

H2O --> [H+] + [OH -]

undergoes a reversible reaction in which both H+ and OH- are generated.

The equilibrium constant for this reaction, called the water dissociation constant, Kw, is 1.0 × 10-14 at 25 °C.

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Mass=4grams Density=2g/ml
Tom [10]

Answer:

you can also get the target audience for the first one in the world 35ml.

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3 years ago
In a constant‑pressure calorimeter, 60.0 mL of 0.300 M Ba ( OH ) 2 was added to 60.0 mL of 0.600 M HCl . The reaction caused the
densk [106]

Answer:

Q sln = 75.165 J

Explanation:

a constant pressure calorimeter:

  • Q sln = mCΔT

∴ m sln = m Ba(OH)2 + m HCl

∴ molar mass Ba(OH)2 = 171.34 g/mol

∴ mol Ba(OH)2 = (0.06 L)(0.3 mol/L) = 0.018 mol

⇒ mass Ba(OH)2 = (0.018 mol)(171.34 g/mol) = 3.084 g

∴ molar mass HCl = 36.46 g/mol

∴ mol HCl = (0.06 L)(0.60 mol/L) = 0.036 mol

⇒ mass HCl = (0.036 mol)(36.46 g/mol) = 1.313 g

⇒ m sln = 3.084 g + 1.313 g = 4.3966 g

specific heat (C):

∴ C sln = C H2O = 4.18 J/g°C

∴ ΔT = 26.83°C - 22.74°C = 4.09°C

heat absorbed (Q):

⇒ Q sln = (4.3966 g)(4.18 J/g°C)(4.09°C)

⇒ Q sln = 75.165 J

8 0
3 years ago
When copper (II) chloride reacts with sodium nitrate, copper (II) nitrate and sodium chloride are formed.
anzhelika [568]

Answer:

How many grams of copper (II) nitrate is formed

3 0
3 years ago
Calculate the net force on the object below.
Anastaziya [24]

Answer:

first we add the same direction. 12N + 32 N=44N .

then we add the forces. 54 up + 44N down= 10N up

8 0
3 years ago
I’ll give the Brainliest
Bond [772]

Answer:

D. is the Answer. ✅

Explanation:

The Moon is 1/4 the size of Earth.

A is not right because Moon isn't a dwarf planet.❌

B is not right because the Moon isn't 1/2 the size of Earth.❌

C is not right because the Moon is no where near as large as Earth.❌

5 0
3 years ago
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