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Rama09 [41]
3 years ago
11

What is the equilibrium constant of pure water at 25°C?

Chemistry
2 answers:
RSB [31]3 years ago
8 0

Answer:

10↑-14

Explanation:

STatiana [176]3 years ago
5 0

Answer: 1.0 × 10-14

Explanation:

Pure water, represented as

H2O --> [H+] + [OH -]

undergoes a reversible reaction in which both H+ and OH- are generated.

The equilibrium constant for this reaction, called the water dissociation constant, Kw, is 1.0 × 10-14 at 25 °C.

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Gala2k [10]

Answer:

Oxygen

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Explanation:

Oxygen=47 percent

Silicon=28 percent

Aluminium=8 percent

Iron=5 percent

Calcium=3.5 percent

Hope it helps :)

Mark me as brainliest

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