Given:
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
To prove:
Triangle ACD and BCE are congruent.
Solution:
In triangle ACD and BCE,
(Given)
(Common angle)
(Given)
In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.
(SAS congruence postulate)
Hence proved.
Answer:
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Answer:
<h3>(-3,1) U (3,8) is the right answer.</h3>
Answer: The variable t us the dependent variable because it affects the amount of money collected, m, each day.
Notice the graph, the domain is just the horizontal area "used up" over the x-axis, so, the graph goees from
![\bf -\cfrac{5x}{2}\quad to\quad \cfrac{5x}{2}\implies domain\implies \left[-\cfrac{5x}{2}\ ,\ \cfrac{5x}{2}\right]](https://tex.z-dn.net/?f=%5Cbf%20-%5Ccfrac%7B5x%7D%7B2%7D%5Cquad%20to%5Cquad%20%5Ccfrac%7B5x%7D%7B2%7D%5Cimplies%20domain%5Cimplies%20%5Cleft%5B-%5Ccfrac%7B5x%7D%7B2%7D%5C%20%2C%5C%20%20%20%5Ccfrac%7B5x%7D%7B2%7D%5Cright%5D)
the range is just, the vertical area "used up" over the y-axis, so, the graph goes to 2 and down to -2, thus
![\bf range\implies [2\ ,\ -2]](https://tex.z-dn.net/?f=%5Cbf%20range%5Cimplies%20%5B2%5C%20%2C%5C%20-2%5D)
