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hammer [34]
4 years ago
10

Math help asap 12,14,16,18,22 show work help asap assig 4

Mathematics
1 answer:
svetoff [14.1K]4 years ago
7 0

Answer:  see below

<u>Step-by-step explanation:</u>

12) 2(x + 4) = 8

   <u> ÷2         </u>  <u> ÷2 </u>

       x + 4  =  4

     <u>      -4 </u>    <u> -4 </u>

             \large\boxed{x=0}

14) 4w - 2(1 - w) = -38

     4w  -2 + 2w = -38

    (4w + 2w) - 2 = -38

              6w  - 2 = -38

             <u>        +2 </u>   <u>  +2 </u>

              6w        = -36

            <u> ÷6        </u>    <u>  ÷6 </u>

                      \large\boxed{w=6}

16) 10(1 - 2y) = -5(2y - 1)

    10 - 20y  = -10y + 5

   <u>      +20y  </u>   <u>+20y      </u>

    10            = 10y  + 5

   <u> -5           </u>    <u>         -5   </u>

               5 = 10y

         <u>   ÷10</u>   <u> ÷10  </u>

            \large\boxed{\dfrac{1}{2}=y}

18)\quad s=\dfrac{1}{2}gt^2\\\\\\.\qquad (2)s=(2)\dfrac{1}{2}gt^2\quad \rightarrow \quad 2s=gt^2\\\\\\.\qquad \dfrac{2s}{t^2}=\dfrac{gt^2}{t^2}\qquad \rightarrow \qquad\large\boxed{\dfrac{2s}{t^2}=g}

22)\quad V=\pi r^2h\\\\\\.\qquad \dfrac{V}{\pi r^2}=\dfrac{\pi r^2h}{\pi r^2}\qquad \rightarrow \qquad \large\boxed{\dfrac{V}{\pi r^2}=h}

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Factoriza C (x) 42x4 − 36x2 + 24x + 12
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When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted
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There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

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The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

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S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16

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t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984

*Use a <em>t</em>-table.

Compute the 95% confidence interval for mean difference as follows:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

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The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

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What value of x is in the solution set of 3(x – 4) ≥ 5x + 2?
alisha [4.7K]
Hey!


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<em>New Equation {Changed by Distribution} :</em>
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<em>Old Equation :</em>
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<em>New Equation {Changed by Inverse} :</em>
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Just by looking at the equation, you can easily tell that it needs to be simplified. So, that's what we'll do next.

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<em>New Equation {Changed by Dividing Both Sides by Two} :</em>
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Seeing as the equation cannot be simplified any further, we have our answer.
<em>The value of x in the inequality </em><span><em>of 3 ( x – 4 ) ≥ 5x + 2, is </em> x </span>≤ -7.

Hope this helps!


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