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3 years ago

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Which numbers are solutions to the inequality x < −7, using the replacement set {−15, −10.5, −7.2, −7, 0}?

2 answers:

slamgirl [31]3 years ago

4 0

Find all the number in the set that are less than -7.

The 'bigger' the negative number seems, the smaller it is.

So -15, -10.5, and -7.2 are all less than -7.

Aleonysh [2.5K]3 years ago

4 0

-15<-10.5<-7.2<-7(<0)

x∈{-15, -10.5, -7.2}. These are less than -7

Answer: B, C, D

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Add x^3 - 4x^2 + 1 to 3x^2 + x <br> Show Your work!

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$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Let's solve ~

$\qquad \sf \dashrightarrow \: (x {}^{3} - 4x {}^{2} + 1) + (3 {x}^{2} + x)$

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2 years ago

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3 years ago

PLEASE ANSWER! Given the functions f(x) = x2 + 6x - 1, g(x) = -x2 + 2, and h(x) = 2x2 - 4x + 3, rank them from least to greatest

Ratling [72]

Answer:

<em>he rank from least to great based on their axis of symmetry: </em>

0, 1, -3 ⇒ g(x), h(x), f(x)

So, <em>option C</em> is correct.

Step-by-step explanation:

A quadratic equation is given by:

$ax^2+bx+c =0$

Here, a, b and c are termed as coefficients and x being the variable.

<em>Axis of symmetry can be obtained using the formula</em>

$x = \frac{-b}{2a}$

Identification of a, b and c in f(x), g(x) and h(x) can be obtained as follows:

$f(x) = x^2 + 6x - 1$

⇒ a = 1, b = 6 and c = -1

$g(x) = -x^2 + 2$

⇒ a = -1, b = 0 and c = 2

$h(x) = 2^2 - 4x + 3$

⇒ a = 2, b = -4 and c = 3

So, axis of symmetry in $f(x) = x^2 + 6x - 1$ will be:

$x = \frac{-b}{2a}$

x = -6/2(1) = -3

and axis of symmetry in $g(x) = -x^2 + 2$ will be:

$x = \frac{-b}{2a}$

x = -(0)/2(-1) = 0

and axis of symmetry in $h(x) = 2^2 - 4x + 3$ will be:

$x = \frac{-b}{2a}$

x = -(-4)/2(2) = 1

<em>So, the rank from least to great based on their axis of symmetry: </em>

0, 1, -3 ⇒ g(x), h(x), f(x)

So, <em>option C</em> is correct.

<em>Keywords: axis of symmetry, functions</em>

<em>Learn more about axis of symmetry from brainly.com/question/11800108</em>

<em>#learnwithBrainly</em>

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