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ELEN [110]
3 years ago
10

How do u correct the graph? ​

Mathematics
1 answer:
konstantin123 [22]3 years ago
5 0

Answer: In my opinion you could just shorten the number of orders so that it's not so long.

Explanation: The numbers can be from every 20 orders so 900, 920, 940...so on.

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Where is the center of CD given C(-6, 12) and D (13, 20)?
Law Incorporation [45]
(3.5, 16)

Midpoint Formula is 
((x1+x2)/2, (y1+y2)/2)
3 0
3 years ago
Which situation involves descriptive statistics?
irinina [24]

Answer:

C

Step-by-step explanation:

Descriptive statistics describe an event that happens over time.  So bowler striking on 1/5 of his throws that night would be an example of descriptive statistics.

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2 years ago
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Find the missing value to the nearest hundredth cos___= 7/18
Oksana_A [137]
Let
cos x=7/18

x=arc cos (7/18)-----> using a calculator-------> x=67.11°-----> x=1.17 radians

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3 0
3 years ago
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Kayleigh babysat for 11 hours this week that was 5 fewer than 2/3 as manyas she baby sat last week, h write an equation to repre
mars1129 [50]

Answer:

10.5 hours

Step-by-step explanation:

To find the number of hours she babysat last week subtract 5 from 11 which is 7 hours. 7 hours is equal to 2/3 of the many hours. If she babysat h hours last week then solve for h using 2/3 h = 7.

Solve the equation by multiplying each side by the reciprocal.

3/2 * 2/3h = 7*3/2

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3 0
3 years ago
The mean number of children among a sample of 15 low-income households is 2.8. The mean number of children among a sample of 19
gtnhenbr [62]

Answer:

Step-by-step explanation:

Let's put the data as below:

n1=15    x1=2.8      s1=1.6       and s1²=2.56

n2=19   x2=2.4     s2=1.7        and s2²=2.89

alpha= 0.05

To test the hypothesis:

H0= There is no sufficient evidence that low income household have fewer children

H1=There is sufficient evidence that low income household have fewer children

Assume that population variances are equal.

the t-static for two samples,

t=\frac{x1-x2}{Sp\sqrt{\frac{1}{n1}-\frac{1}{n2} \\} } } ~t with min (n1-1,n2-1)df

The pooled variance estimate Sp equals:

Sp^{2}=\frac{(n1-1)s1^{2}+(n2-1)s2^{2}  }{n1+n2-2}

Sp²=2.7456

Sp=1.65699

Degrees of freedom=n1+n2-2=32

Under null hypothesis:

tcal=\frac{|2.8 - 2.4|}{1.6599\sqrt{\frac{1}{15}+\frac{1}{19}  } }

tcal=0.6989

The critical value ttab=2.0369 for alpha=0.05

So we reject our null hypothesis H0

So there is sufficient evidence that low income households have fewer children than high income households

6 0
3 years ago
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