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SSSSS [86.1K]
3 years ago
13

2x - 6x + 9 factored

Mathematics
1 answer:
sergejj [24]3 years ago
7 0
I might not be correct please let me know !! But as of right now I think the answer is

-(4x-9)
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Shown below is a prism.
tigry1 [53]

Answer:

Volume = 126 cm^2

Step-by-step explanation:

You don't exactly know what the base looks like, but it doesn't matter. The volume of a Prism is Base * height.

Solution

V = Base (which is the Cross sectional Area) * Length

V = 21 cm^2 * 6 cm

V = 126 cm^2

8 0
3 years ago
Phillip is standing across the classroom from his desk. He walks x steps in a straight line to his right, turns left at a 90° an
Rainbow [258]
For this case, we can model the problem as a triangle with a right angle.
 Where,
 x, y: lengths of the sides of the triangle
 d: hypotenuse of the triangle
 We then have the following relationship:
 d ^ 2 = x ^ 2 + y ^ 2

 Clearing d we have:
 d = \sqrt{ x^2 + y^2}
 Answer:
 
A functions that would best model the situation above is:
 
D square root
6 0
4 years ago
What percent is 25 is 12
Ray Of Light [21]

Answer: 48%

Step-by-step explanation:

I believe you meant, what percent of 25 is 12.

In that case, you would do 12/25 which equals 0.48

To convert a decimal into a percent, you would move the decimal point over 2 digits to the right. That would make 0.48 into 48%

So 48% is the answer.

Hope this helps :)

8 0
3 years ago
Read 2 more answers
A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
EleoNora [17]

Answer:

a) P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

b) P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

c) P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

d) E(X) = 20*0.2= 4

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=20, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Part a

We want this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

Part b

We want this probability:

P(X=4)

And using the probability mass function we got:

P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

Part c

We want this probability:

P(X>3)

We can use the complement rule and we got:

P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

Part d

The expected value is given by:

E(X) = np

And replacing we got:

E(X) = 20*0.2= 4

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=b%20%2B%20%5Csqrt%7Bb%7D%20%5C%3A%20%5C%3A%20%5C%3A%20%5C%3A%20-%2012" id="TexFormula1" title=
insens350 [35]
So this is the fully factorized answer

8 0
3 years ago
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