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Valentin [98]
3 years ago
5

Find the remainder when f(x) = x3 + 14x2 − 7x − 10 is divided by x − 3

Mathematics
2 answers:
loris [4]3 years ago
5 0

Answer:

-122

Step-by-step explanation:

f(3) = 3³ + 14(3)² - 7(3) - 10

    = 27 + 126 - 21 - 10

    = - 122 is the remainder

hoa [83]3 years ago
3 0

Answer:

remainder = 122

Step-by-step explanation:

Using the remainder theorem to evaluate the remainder

Division by x - 3 , thus evaluate f(3) for remainder

f(3) = 3³ + 14(3)² - 7(3) - 10

     = 27 + 126 - 21 - 10

     = 122 ← remainder

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Find the area of the circle
gladu [14]

Answer:

its 452.2

Step-by-step explanation:

because im right

5 0
3 years ago
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Is the following relation a function? (4,2), (1,1), (0,0), (1, -1), (4, -2). Give the domain and range.
Vlada [557]
(x,y)
to be  a function
for every x, ther must be only 1 y to corespond to it
basically, x must NEVER repeat with a different y
list them

ah, we see (1,1) an d(1,-1)
also (4,2) and (4,-2)
double offense
1 repeats with 1 and -1
4 repeats with 2 and -2

not a function

domain is all x values
range is all y values
if they repeat, don't list them

domain=(0,1,4)
range=(-2,-1,0,1,2)
8 0
3 years ago
There are 276 students.
Lynna [10]

Step-by-step explanation:

Number of males is

  • 276 - 158 = 118

Number of males not enrolled

  • 118 - 82 = 36

Number of females not enrolled

  • 158 - 102 = 56

(a)

The table based on data is

<u>                 Enrolled        Not enrolled      Total  </u>

<u>Male            82                  36                     118    </u>

<u>Female        102                56                     158   </u>

Total            184                 92                     276

(b)

Percentage of students were males that went to magic college

  • enrolled male / total students =           (use table above)
  • 82/276*100% = 29.71% (rounded)

(c)

Percentage of females went to magic college

  • enrolled female / total female =           (use table above)
  • 102/158*100% = 64.56% (rounded)
7 0
2 years ago
You have two nickels three dimes and a quarter. Using at least one of each coin, how many different amounts of money can you mak
Slav-nsk [51]
2 nickels (5 cents each)
3 dimes (10 cents each)
1 quarter (25 cents)

1 nickel, 1 dime, 1 quarter
5 + 10 + 25 = 40

2 nickels, 1 dime, 1 quarter
5(2) + 10 + 25 = 45

1 nickel, 2 dimes, 1 quarter
5 + 10(2) + 25 = 50

1 nickel, 3 dimes, 1 quarter
5 + 10(3) + 25 = 60

2 nickels, 2 dimes, 1 quarter
5(2) + 10(2) + 25 = 55

2 nickels, 3 dimes, 1 quarter
5(2) + 10(3) + 25 = 65

You can make 6 different amounts. 
You could also find this by multiplying however many coins you have all together.
2 * 3 * 1 = 6
6 0
3 years ago
The product of three consecutive integers is 210. What is their sum?
Tcecarenko [31]

Answer:

3 consecutive no.s are

5×6×7=210

sum of them is= 5+6+7

=18

So, I hope. it helps !!

6 0
2 years ago
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