Answer:
The remaining liquid has a volume of 345.4 cm³.
Step-by-step explanation:
To solve this question we first need to calculate the volume of each container.
Cylindrical:
Volume = h*pi*r² = 14*3.14*(5)² = 1099 cm³
Cone:
Volume = (1/3)*h*pi*r² = (1/3)*20*3.14*(6)² = 753.6 cm³
Since the liquid from the cylinder was transfered to the cone until the latter was full, then what remains in the cylinder is it's original volume minus the cone volume. So we have:
remaining liquid = 1099 - 753.6 = 345.4 cm³
Step-by-step explanation:
-5c+5c+2c–6c–16=c
-16c - 16=c
-16 = c + 16c
-16 = 17c
-16/17 = c
The one that is filled the less would be the garbage can because the truck would get filled even more.
Answer:
I believe its 10 to the -9th power.
Step-by-step explanation:
Answer:
-6 and 1
Step-by-step explanation:
If you separate the different powers (^), you have -m^3 - 5m^3 and -m^2 + 2m^2.
-m^3 - 5m^3 = -6m^3
-m^2 + 2m^2 = m^2 or 1m^2
