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atroni [7]
3 years ago
5

Two equivalent ratios 3:4 What are 2 equivalent ratios to 3:4

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

1:4 and 2:3

Step2247 [10]3 years ago
4 0

Answer:

9:12 and 12:16

Step-by-step explanation:

3/4 = 0.75

9/12 = 0.75

12/16 = 0.75

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Which of the following is the product of the rational expressions shown<br> below?<br> 3/x+7 x 4/x
kotykmax [81]

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31/x

Step-by-step explanation:

im assuming thats a 7*

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Xy has endpoints at X(2,-3) and Y(-1,2) what is the length of XY
goldenfox [79]

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6

Step-by-step explanation:

The length form -1 to 2 is 3

The length from -3 to 2 is 5

√3²+5² = √9+25 =√36=6

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A 5 1/2 ounce straws berry smoothie has 28 1/2 protein in it. Approximately how many grams of protein per ounce are in the smoot
yuradex [85]
The answer is 5.18 and the 18 is repeated.
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3 years ago
Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9
tatiyna

Answer:

The solution to the system of equations is

\begin{gathered} x=\frac{179}{13} \\  \\ y=-\frac{279}{39} \\  \\ z=-\frac{48}{13} \end{gathered}

Explanation:

Giving the system of equations:

\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)

Subtracting (3) from 3 times (1), we have

3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

\begin{gathered} 13z=-48 \\  \\ z=-\frac{48}{13} \end{gathered}

Using the value of z obtained in (5), we have

\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\  \\ 3y+\frac{240}{13}=-3 \\  \\ 3y=-3-\frac{240}{13} \\  \\ 3y=-\frac{279}{13} \\  \\ y=-\frac{279}{39} \end{gathered}

Using the values obtained for y and z in (1), we have

\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\  \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\  \\ x-\frac{231}{13}=-4 \\  \\ x=-4+\frac{231}{13} \\  \\ x=\frac{179}{13} \end{gathered}

8 0
1 year ago
What are the solutions of x^2+6x-6=10
Alchen [17]

Answer:

ifhofgoefouegf

Step-by-step explanation:

4 0
3 years ago
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