Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
Step-by-step explanation:
Number Price per Total Commission Total cost
of Shares Share (At 6% of total)
100 $16.25 $1625 1625+97.5 = $1722.5
100 $11.31 $1131 1131+67.86=$1198.86
40 $9.15 $366 366+21.96=$387.96
100 $15.27 $1527 1527+91.62=$1618.62
100 $13.22 $1322 1322+79.32=$1401.32
