A local school needs to paint the floor of its theater room, where the length of the floor, x, is at least 12 feet. The width of
the floor is 4 feet less than the length. It will have a stage and a closet, and the remaining area of the floor will be painted. The dimensions are shown in the diagram:
Let A represent the painted area, in square feet, of the floor. Choose the correct equation to solve for area (A).
A = x(x − 4) + 0.5(6)(x − 4) + 2(7)
A = x(x − 4) − 0.5(6)(x − 4) − 2(7)
A = x(x − 4) − (6)(x − 4) − 2(7)
A = x(x − 4) + (6)(x − 4) + 2(7)
Let A represent the painted area, in square feet, of the floor. Choose the correct equation to solve for area (A).
A = x(x − 4) + 0.5(6)(x − 4) + 2(7)
A = x(x − 4) − 0.5(6)(x − 4) − 2(7)
A = x(x − 4) − (6)(x − 4) − 2(7)
A = x(x − 4) + (6)(x − 4) + 2(7)
1 answer:
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Law of Cosines says
Choice C
Hello from MrBillDoesMath!
Answer:
4/sin(80)
which is approximately 4.06
Discussion:
From the triangle, not drawn too accurately (see attachment)
sin(80) = side opposite /hypotenuse =>
sin (80) = 4/c => multiply both sides by "c"
c sin(80) = 4/c * c =>
c sin(80) = 4 => divide both sides by sin(80)
c = 4/sin(80)
and 4/sin(80) is approximately 4.06
Thank you,
MrB
