All categories

2 years ago

GUYS HELPP ME!! Sketch a graph showing her distance from home. Also help me answer the questions below!

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

6 0

I've uploaded a picture, refer back to it .

In the beginning, Annie's distance is increasing(in brown), but decreases only once(in orange), when she went back to get her homework.

It also increases as she goes on the freeway fast(in blue) so her distance increases rapidly in a short amount of time.

Distance stays the same for a while, as they are stopped at a light for a couple of minutes(in yellow)

Increases one more time, when they approach the school slowly. (in pink)

2. Annie travels the fastest (highlighted in blue) when she and her brother get on the freeway and reach high speeds. The graph shows this by showing a steep ascent, representing a rapid increase in distance in a short amount of time.

Hope this helps and please consider marking branliest.

You might be interested in

Please help!! Which equation represents the parabola shown on the graph?

MatroZZZ [7]

X^2=6y Hope this helps!

6 0

2 years ago

Read 2 more answers

A globe of the moon has a radius of 10 inches. Find the volume of the globe. Round your answer to the nearest whole number.

Mariulka [41]

It would be 4,189 m3

4 0

2 years ago

Fiction G is shown on the graph Which function represents G

MrMuchimi

Answer:

The answer would be B.

7 0

2 years ago

Write the equation of circle b with center B(-2,3) that passes through (1,2)

professor190 [17]

Answer:

$(x+2)^2 + (y-3)^2 = 10$

Step-by-step explanation:

The standard equation for circle is

$(x-a)^2 + (y-b)^2 = r^2$

where point (a,b) is coordinate of center of circle and r is the radius.

______________________________________________________

Given

center of circle =((-2,3)

let r be the radius of circle

Plugging in this value of center in standard equation for circle given above we have

$(x-a)^2 + (y-b)^2 = r^2 \ substitute (a,b) \ with (-2,3) \\=>(x-(-2))^2 + (y-3)^2 = r^2 \\=>(x+2)^2 + (y-3)^2 = r^2 (1)$

Given that point (1,2 ) passes through circle. Hence this point will satisfy the above equation of circle.

Plugging in the point (1,2 ) in equation 1 we have

$\\=>(x+2)^2 + (y-3)^2 = r^2 \\=> (1+2)^2 + (2-3)^2 = r^2\\=> 3^2 + (-1)^2 = r^2\\=> 9 + 1 = r^2\\=> 10 = r^2\\=> r^2 = 10\\$

now we have value of r^2 = 10, substituting this in equation 1 we have

Thus complete equation of circle is $=>(x+2)^2 + (y-3)^2 = r^2\\=>(x+2)^2 + (y-3)^2 = 10$

7 0

3 years ago

Find the equation of the linear function 'g' going through (20,5) and (-5,-8). Use 'u' for your input variable.

frosja888 [35]

Answer:

See below

Step-by-step explanation:

Use the slope-intercept form, which will be in this case:

g(u) = mu + b, where m is the slope, b is the y- intercept

Find the slope:

$m=(y_2-y_1)/(x_2-x_1)$
$m=(-8-5)/(-5-20)=(-13)/(-25)=13/25$

Find the value of the y-intercept:

$5=1/25*20+b$
$b=5-4/5=21/5$

The equation is:

$g(u)=\frac{13}{25} u+\frac{21}{5}$

3 0

2 years ago