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Step2247 [10]
3 years ago
9

HELP ME PLEASE PLEASE

Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:6=C 7=C

Step-by-step explanation:

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Write an equation of the line in slope-intercept form given the slope is -5 and the y-intercept is 7
elena-14-01-66 [18.8K]

Answer: Y= -5x + 7

Step-by-step explanation:

Y=Mx+b is slope intercept form therefore

The M is replaced with the slope and the b is the y- intercept hope this helps

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3 years ago
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Which of the following pairs of equations represents lines that are parallel? 
vaieri [72.5K]

Answer:

D

Step-by-step explanation:

The slope of the parallel lines have the same slope. So since D is the only answer choice with the same slope, the answer is D.

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3 years ago
What is the value of StartFraction negative 2 (7 minus 15) over 4 EndFraction? –4 –2 2 4
BartSMP [9]

Answer:

The Correct answer is last option i.e 4.

Therefore,

-2(\dfrac{7-15}{4})=4

Step-by-step explanation:

Given:

StartFraction negative 2 (7 minus 15) over 4 EndFraction

Means

-2(\dfrac{7-15}{4})

-2(\dfrac{-8}{4})

-2(-2)

Minus sign will enter in it and ( - ) × ( - ) = ( + )

4

Therefore,

-2(\dfrac{7-15}{4})=4

3 0
3 years ago
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A professor believes the class he is teaching in the current semester is above the average of the classes he has taught. In orde
MakcuM [25]

Answer:

1) Since we know the info from all the students that he teaches and we know the population deviation from past data we can use a z test to check the hypothesis

2) t=\frac{82-78}{\frac{15}{\sqrt{120}}}=2.921    

3) p_v =P(Z>2.921)=0.0017  

Since the p value is lower than the significance level of 0.01 we have enough evidence to reject the null hypothesis in favor of the alternative hypothesis

4) For this case since we reject the null hypothesis we have enough evidence ot conclude that the scores for this semester are above the historical value of 78 so then the claim stated by the teacher makes sense

Step-by-step explanation:

Part 1

Since we know the info from all the students that he teaches and we know the population deviation from past data we can use a z test to check the hypothesis

Part 2

\bar X=82 represent the sample mean  for the scores

\sigma=15 represent the population standard deviation

n=120 represent the sample selected

\alpha=0.01 significance level  

System of hypothesis

He wants to test if the group for this current semester is above the average of the classes he has taught (mean 78), the system of hypothesis are:

Null hypothesis:\mu \leq 78  

Alternative hypothesis:\mu > 78  

Since we know the population deviation we can use the following statistic

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{82-78}{\frac{15}{\sqrt{120}}}=2.921    

Part 3

We can calculate the p value for this test with this probability taking in count the alternative hypothesis:

p_v =P(Z>2.921)=0.0017  

Since the p value is lower than the significance level of 0.01 we have enough evidence to reject the null hypothesis in favor of the alternative hypothesis

Part 4

For this case since we reject the null hypothesis we have enough evidence ot conclude that the scores for this semester are above the historical value of 78 so then the claim stated by the teacher makes sense

5 0
4 years ago
What is 42 to the power of 9 divided by 2.and Multipied by 6?
bekas [8.4K]
Exact form:
1220014151548416

Decimal form:
1.22001415*10^15
5 0
4 years ago
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