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alexandr1967 [171]
3 years ago
13

A bank advertises an interest rate of 4% per year, compounded monthly

Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Given :

Interest rate , r = 4 %.

To Find :

The APY .

Solution :

APY is given by :

APY=(1+\dfrac{r}{n})^n-1

Here , r is compound interest and n is number of time compounded .

So ,

APY=(1+\dfrac{r}{n})^n-1\\\\APY=(1+\dfrac{4}{12})^{12}-1\\\\APY=30.57\%

Therefore , APY is 30.57 % .

Hence , this is the required solution .

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The ratio of the number of hours it takes the three pipes A, B and C to fill an olympic pool is 4:9:12. Answer each of the follo
Andru [333]

Answer:

your answer is 6 hours

Step-by-step explanation:

you have the 2nd pipe takes 72 hours so then you multiply 4 x 9 x 12 which is 432 and then you divide 432 by 72 which is 6 so it would be 6 hours

hope it helps ^^

4 0
3 years ago
Read 2 more answers
In how many ways can 4 people sit down in 6 seats in a row
Wewaii [24]

Answer:

360

Step-by-step explanation:

1st person can be seated in 6 ways, 2nd person in 5 ways, 3rd person in 4 ways and 4th person in 3 ways.

Required number of ways =(6×5×4×3)=360.

Hope this helps!!! Have a great day!! :D

5 0
3 years ago
The box shown has a volume of 8 cubic inches.
Eduardwww [97]

Answer:

The answer is 2

Step-by-step explanation:

If we use the formula for volume LWH=V. We also take in the fact that a cube has the same measure on every side. and we input 2 for L , W , and H

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5 0
2 years ago
An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0
3 years ago
Can some also explain it to me how to identify if it’s continuous exponential
sweet-ann [11.9K]
B is the correct answer


hope this helps
8 0
3 years ago
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