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alexandr1967 [171]
4 years ago
13

A bank advertises an interest rate of 4% per year, compounded monthly

Mathematics
1 answer:
Darina [25.2K]4 years ago
4 0

Given :

Interest rate , r = 4 %.

To Find :

The APY .

Solution :

APY is given by :

APY=(1+\dfrac{r}{n})^n-1

Here , r is compound interest and n is number of time compounded .

So ,

APY=(1+\dfrac{r}{n})^n-1\\\\APY=(1+\dfrac{4}{12})^{12}-1\\\\APY=30.57\%

Therefore , APY is 30.57 % .

Hence , this is the required solution .

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In the figure,ABC is a right-angled triangle.PQ=24cm,PR=45cm and T is a point on QR such that PT丄QR.Find PT.
snow_tiger [21]

RQ² = RP² + PQ²

RQ² = 45² + 24²

RQ² = 2025 + 576

RQ² = 2601

RQ = 51

PT/PR = PQ/RQ

PT/45 = 24/51

PT = (24/51) × 45

PT = (8/17) × 45

PT = 360/17

8 0
3 years ago
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I don’t understand Please help!
AlekseyPX

Answer:

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An antelope can run at a speed of 61 miles per hour. what is this speed in yards per second? round to nearest hundredths
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3 0
3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
the length and breadth of a hall are 20m and 15m respectively. find the area of 4 Walls of the hall if the height of the hall is
oksano4ka [1.4K]

Answer:

300

Step-by-step explanation:

area=20*15=300

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