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FrozenT [24]
3 years ago
10

What is the main ideas in the periodic law?​

Chemistry
1 answer:
prohojiy [21]3 years ago
6 0

Answer:

The Periodic Law shows that the physical and chemical properties of the elements recur in a systematic and predictable way when the elements are arranged in order of increasing atomic number.

Hope this helps ⊂◉‿◉つ

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How many atoms is in 222.25 grams of copper
irinina [24]

Answer:

14,138.985

Explanation:

I think!

multiply the amount of atoms in copper by the amount of grams. hope this helped

7 0
4 years ago
Equation: CH4 + 202 CO2 + 2H20
jeka94

Answer:

2:1

1.2 × 10² g

Explanation:

Step 1: Write the balanced combustion equation

CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to CH₄ is 2:1.

Step 3: Calculate the moles of CH₄ required to react with 15 moles of O₂

We will use the previously established molar ratio.

15 mol O₂   1 mol CH₄/2 mol O₂ = 7.5 mol CH₄

Step 4: Calculate the mass corresponding to 7.5 moles of CH₄

The molar mass of CH₄ is 16.04 g/mol.

7.5 mol × 16.04 g/mol = 1.2 × 10² g

4 0
3 years ago
Your Turn!
crimeas [40]

Answer:

because.......

...........

.........

3 0
3 years ago
Suppose you wish to separate a mixture of fine particles of gold and sand, neither of which is soluble in water. if you add liqu
Greeley [361]

The mixture can be separated as shown in the flow chart

4 0
3 years ago
A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em
Neporo4naja [7]

Answer: The empirical formula is H_2S_2O_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles

Mass of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = \frac{1.8}{1.8}=1

For S = \frac{1.8}{1.8}=1

For O =\frac{2.6}{1.8}=1.5

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is H_2S_2O_3

7 0
3 years ago
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