Answer:
The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Past studies suggest this proportion will be about 0.15
This means that 
Find the sample size needed if the margin of error of the confidence interval is to be about 0.04
This is n when M = 0.04. So
Rounding up
The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.
Answer:
hope my answer is helpful to you
plz mark me as brainlist and also follow me
Answer:the charge for admission is $6 and the cost of a ride is $2
Step-by-step explanation:
Let x represent the charge for admission.
Let y represent the cost of a ride.
An amusement park charges admission plus a fee for each ride. Admission plus two rides costs $10. This means that
x + 2y = 10 - - - - - - - - - - - - - 1
Admission plus five rides cost $16. This means that
x + 5y = 16 - - - - - - - - - - -- - -2
Subtracting equation 2 from equation 1, it becomes
- 3y = - 6
y = - 6/- 3
y = 2
Substituting y = 2 into equation 1, it becomes
x + 2×2 = 10
x = 10 - 4 = 6
Around 4 lbs. because 3 apples to about 1 lbs. IM JUST ESTIMATING
9514 1404 393
Answer:
$(4/3)X
Step-by-step explanation:
Working 12 hours, Samia gets paid for the first 8 hours ...
8 · ($X) = $8X
For the remaining 4 hours, she is paid ...
4 · ($2X) = $8X
Then for 12 hours, she is paid a total of ...
$8X +$8X = $16X
Her average hourly pay is then ...
total pay / total hours = $16X/12 = $(4/3)X . . . average hourly pay
