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4 years ago

Does the earth behave like a magnet how do you prove it

1 answer:

5 0

Take any item that's magnetized. With a sharpie or a drop of nail polish, make a small mark on one end of the item. Then, hang it up by a thread, in such a way that its two ends are at the same height off the floor, and it's free to turn on the thread.

After it settles down and stops turning and wiggling, it'll come to rest with the marked end pointing in the same direction EVERY TIME you try this.

The only thing that makes a magnet point in the same direction every time is another magnet.

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Can someone help me :)

Mamont248 [21]

Answer:

mass= 60kg

velocity= 10m/s

momentum = mass × velocity

p=m×v

p= 60×10

p= 600kgm/s

5 0

3 years ago

When a nerve cell depolarizes, charge is transferred across the cell membrane, changing the potential difference. For a typical

igomit [66]

Answer:

1.8nA

Explanation:

I = dq/dt

I = 9.0 × 10 ^-12 / 0.5 × 10^-3

I = 1.8 × 10× 10^-8

I = 1.8nA

6 0

3 years ago

Read 2 more answers

Find the velocity and displacement of a motor starting from a fixed position after moving 15 s at an acceleration of 2 m s ^ -2.

podryga [215]

Answer:

hope it helps you.......

7 0

3 years ago

A Answer the following questions 1. On a cold wintery day, you burn firewood to keep yourself warm. The firewood undergoes a cha

Gnom [1K]

Answer:

heating prosedure takes place the opposite of condensation

8 0

3 years ago

a 2-kg bowling ball is 2.5 meters off the ground on a post when it falls. Just before it reaches the ground, it is traveling 7 m

Lilit [14]

“The mechanical energy is conserved" in the given system is true out of all given options.

Answer: Option 2

<u>Explanation: </u>

According to law of conservation of energy, the energy will neither be created nor be destroyed, irrespective of the type of energy. As in the present case, the ball is bowled and it is travelling to ground, so the mechanical energy is working in this case. Thus the mechanical energy will be conserved. Even it can be shown as follows.

As the 2 kg ball is travelling with a speed of 7 m/s, the kinetic energy exhibited by the ball while falling to ground will be

$\text {Kinetic energy}=\frac{1}{2} \times \text { mass of the ball } \times\left(\text { speed of the ball) }^{2}\right.$

Thus, applying given values, we get,

$\text {Kinetic energy exhibited by the ball}=\frac{1}{2} \times 2 \times 7 \times 7=49 \mathrm{J}$

Similarly, as the ball is 2.5 m above ground, the potential energy will also be exhibited by the ball at that position. So the potential energy will be

$\text {Potential energy}=\text {Mass} \times \text {acceleration} \times \text {height}$

Thus,

$\text { Potential energy exhibited by the ball }=2 \times 9.8 \times 2.5=49 \mathrm{J}$

Thus as the magnitude of kinetic energy is equal to the magnitude of potential energy exhibited by the ball with varying direction, the net energy will be zero. This is because the kinetic energy will be acting in opposite direction to the potential energy exhibited by the ball. Hence as the net energy is zero, the mechanical energy is conserved.

3 0

4 years ago