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Allisa [31]
3 years ago
14

A 14,700 N car is traveling at 25 m/s. The brakes are applied suddenly, and the car slides to a stop. The average braking force

between the tires and the road is 7100 N. How far will the car slide once the brakes are applied? ...?
Physics
1 answer:
Vlada [557]3 years ago
7 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

vo = 25 m/sec 
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
<span>7100 N = (1500 kg) a </span>
<span>a = 4.73333333333 m/sec² </span>
<span>And now, we can use a velocity formula to find the distance traveled: </span>
<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
<span>0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d </span>
<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
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Mass of car = 1098 kg

Explanation:

Here law of conservation of momentum is applied.

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Final momentum = 4350 x 4.55 + m x 11.5 = 19792.5+11.5m

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A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
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Answer:

9.43 m/s

Explanation:

First of all, we calculate the final kinetic energy of the car.

According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:

W=K_f - K_i

where

W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)

K_f is the final kinetic energy

K_i = 66,120 J is the initial kinetic energy

Solving,

K_f = K_i + W = 66,120 + (-36,733)=29,387 J

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Solving for v, we find

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Starting from the front door of your ranch house, you walk 50.0 m due east to your windmill, and then you turn around and slowly
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Answer:

Average velocity

v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}

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S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}

Explanation:

(a)Average velocity

We have to find the average velocity. We know that velocity is defined as the rate of change of displacement with respect to time.

To find the average velocity we have to find the total displacement.

since displacement along east direction is 50m

and displacement along west=40m

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d=50m-40m\\d=10m

total time,

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therefore, average velocity

v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}

(b)Average Speed:

Average speed is defined as the ratio of total distance to the total time

it means

Average speed= total distance/total time

here total distance,

D= 50m+40m\\D=90m

and total time,

t= 28s+40s\\t=70s

therefore,

Average speed,

S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}

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