Answer:
Volume will be 15 mL. Solution:- If we look at the given information then it is Boyle's law as the temperature is constant and the volume changes inversely as the pressure changes. So, the volume of the air bubble at the surface will be 15 mL.
Given Information:
Current = I = 20 A
Diameter = d = 0.205 cm = 0.00205 m
Length of wire = L = 1 m
Required Information:
Energy produced = P = ?
Answer:
P = 2.03 J/s
Explanation:
We know that power required in a wire is
P = I²R
and R = ρL/A
Where ρ is the resistivity of the copper wire 1.68x10⁻⁸ Ω.m
L is the length of the wire and A is the area of the cross-section and is given by
A = πr²
A = π(d/2)²
A = π(0.00205/2)²
A = 3.3x10⁻⁶ m²
R = ρL/A
R = 1.68x10⁻⁸*(1)/3.3x10⁻⁶
R = 5.09x10⁻³ Ω
P = I²R
P = (20)²*5.09x10⁻³
P = 2.03 Watts or P = 2.03 J/s
Therefore, 2.03 J/s of energy is produced in 1.00 m of 12-gauge copper wire carrying a current of 20 A
We want to find the combined volume of 3 tennis balls. We will get that the combined volume is 493.7 cm^3
First, remember that for a sphere of diameter D, the volume is:
![V = \frac{4}{3}*3.14*(\frac{D}{2})^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%2A3.14%2A%28%5Cfrac%7BD%7D%7B2%7D%29%5E3)
Where 3.14 is pi.
Here we know that the average diameter of a tennis ball is 6.8cm, then we can replace that in the above equation to find the volume (in average) of a single tennis ball:
![V = \frac{4}{3}*3.14*(\frac{6.8cm}{2})^3 = 164.5 cm^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%2A3.14%2A%28%5Cfrac%7B6.8cm%7D%7B2%7D%29%5E3%20%3D%20164.5%20cm%5E3)
Now, in 3 balls of tennis, the combined volume will be 3 times the above one, this is:
![3*V = 3*164.5cm^3 = 493.7 cm^3](https://tex.z-dn.net/?f=3%2AV%20%3D%203%2A164.5cm%5E3%20%3D%20493.7%20cm%5E3)
If you want to learn more about volumes, you can read:
brainly.com/question/10171109
The correct selections are C, C, B, D, A, B, and A .