if 4% of packages get lost in the mail, then which decimal best represent the amount of packages lost in the mail?

I NEED HELP PLEASE. LOOK AT PICTURE

Bond [772]

Answer:

Part 1) $\frac{a^4}{4b^2}$

Part 2) $-\frac{v^9}{w^6}$

Step-by-step explanation:

we know that

When divide exponents (or powers) with the same base, subtract the exponents

Part 1) we have

$\frac{3a^{2}b^{-4}}{12a^{-2}b^{-2}}=(\frac{3}{12})(a^{2+2})(b^{-4+2} )=\frac{1}{4}a^{4}b^{-2}=\frac{a^4}{4b^2}$

Part 2) we have

$\frac{v^3w^{-3}}{-v^{-6} w^3} =-v^{3+6}w^{-3-3}=-v^9w^{-6}=-\frac{v^9}{w^6}$

6 0

2 years ago

Morgan uses 2 oz of dog shampoo to bathe her dog each week. After 4 wk, 34 oz of shampoo remains.

Flauer [41]

The amount of shampoo required by Morgan each week to bathe her dog = 2 oz
So
The amount of shampoo required by Morgan in 7 days to bathe her dog = 2 oz
The amount of shampoo remaining after 4 weeks = 34 oz
So the amount of shampoo remaining after (4 * 7) days = 34 oz
The amount of shampoo remaining after 28 days = 34 oz
The amount of shampoo that Morgan uses in 28 days = (2/7) * 28 oz
= 2 * 4 oz
= 8 oz
Then
8 oz of shampoo is required by Morgan in = 28 days
Then
34 oz of shampoo will be used in = (28/8) * 34 days
= 7 * 17 days
= 119 days
So
The total number of
days before the bottle becomes empty = 119 + 8 oz
= 127 days

6 0

3 years ago

Which answer explains the correct way to move the decimal to find the product of 15.31 × 103?

cricket20 [7]

A. two places to the left

8 0

3 years ago

If Kevin wants a 90 average in math after 5 tests and his first 4 tests are 76, 92, 89 and 97 what does he need on the fifth tes

Keith_Richards [23]

You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.

4 0

3 years ago

Read 2 more answers

ILL BRAINLIEST YOU PLEASE HELP ME

gtnhenbr [62]

Answer:

Option C

The length of RT is 14

Step-by-step explanation:

For a given Right Triangle

m∠R = 90°, RG = 17, TG = 22

Now, <u>By Pythagoras Theorem</u>

(RT)² + (RG)² = (TG)²

(RT)² = (TG)² - (RG)²

(RT)² = (22)² - (17)²

(RT)² = 484 - 289

(RT)² = 195

RT = √195

RT = √195 = 13.96 = 14

Thus, The length of RT is 14

<u>-TheUnknownScientist</u>

4 0

3 years ago

if 4% of packages get lost in the mail, then which decimal best represent the amount of packages lost in the mail?​

if 4% of packages get lost in the mail, then which decimal best represent the amount of packages lost in the mail?