1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eva8 [605]
3 years ago
9

Tamir is a kickboxing instructor who will be teaching classes at a local gym. To get certified as an instructor, he spent a tota

l of $109. Tamir will be earning a base salary of $95 per month from the gym, plus an additional $14 for every class he teaches. If Tamir teaches a certain number of classes during his first month as an instructor, he will earn back the amount he spent on certification. How much will Tamir's expenses and earnings be? How many classes will that take
Mathematics
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

It will take one class

Step-by-step explanation:

Tamir will earn $109 every month (his base salary and additional $14 equals to $109). This means after one class he will be able to earn back the money he spent of becoming an instructor.

You might be interested in
Need help pls pls pls pls pls pls
Crazy boy [7]

Answer:

d.

Step-by-step explanation:

hi I think its d, sorry if I'm wrong

6 0
3 years ago
Asnwer aswer answer answer plz ASWER ANSWER ANSWER ANSWERR PLZ ANSWEER I NEED ANSWER PLZZZZZ!!!! i need help HELP!!!
Ksenya-84 [330]

Answer:

29,035.43 meters

Step-by-step explanation:

What we know:

- The elevation of the shore of the Dead Sea is -1,344.99 meters.

- The summit of Mt. Everest is 30,380.42 meters above the Dead Sea.

So, we just add the two values.

30,380.42 + (-1,344.99)

We can rewrite this as 30,380.42 - 1,344.99 since adding a negative is the same as subtracting that number.

And we get 29,035.43 meters as the elevation or height of Mt. Everest.

7 0
2 years ago
A right triangle has a hypotenuse of 153 centimeters and a leg of 72 centimeters. What is the length of the other leg?
Luba_88 [7]
81 cent.........................................................                                               
7 0
3 years ago
In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6 years according to the U.S. Depa
marissa [1.9K]

Answer:

The <em>95% confidence interval</em> for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Step-by-step explanation:

The <em>confidence interval</em> of the mean is given by the next formula:

\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}} [1]

We already know (according to the U.S. Department of Justice):

  • The (population) standard deviation for this case (mean age of an inmate on death row) has a standard deviation of 9.6 years (\\ \sigma = 9.6years).
  • The number of observations for the sample taken is \\ n = 32.
  • The sample mean, \\ \overline{x} = 38.9 years.

For \\ z_{1-\frac{\alpha}{2}}, we have that \\ \alpha = 0.05. That is, the <em>level of significance</em> \\ \alpha is 1 - 0.95 = 0.05. In this case, then, we have that the <em>z-score</em> corresponding to this case is:

\\ z_{1-\frac{\alpha}{2}} = z_{1-\frac{0.05}{2}} = z_{1-0.025} = z_{0.975}

Consulting a cumulative <em>standard normal table</em>, available on the Internet or in Statistics books, to find the z-score associated to the probability of, \\ P(z, we have that \\ z = 1.96.

Notice that we supposed that the sample is from a population that follows a <em>normal distribution</em>. However, we also have a value for n > 30, and we already know that for this result the sampling distribution for the sample means follows, approximately, a normal distribution with mean, \\ \mu, and standard deviation, \\ \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}.

Having all this information, we can proceed to answer the question.

Constructing the 95% confidence interval for the current mean age of death-row inmates

To construct the 95% confidence interval, we already know that this interval is given by [1]:

\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

That is, we have:

\\ \overline{x} = 38.9 years.

\\ z_{1-\frac{\alpha}{2}} = 1.96

\\ \sigma = 9.6 years.

\\ n = 32

Then

\\ 38.9 \pm 1.96*\frac{9.6}{\sqrt{32}}

\\ 38.9 \pm 1.96*\frac{9.6}{5.656854}

\\ 38.9 \pm 1.96*1.697056

\\ 38.9 \pm 3.326229

Therefore, the Upper and Lower limits of the interval are:

Upper limit:

\\ 38.9 + 3.326229

\\ 42.226229 \approx 42.23 years.

Lower limit:

\\ 38.9 - 3.326229

\\ 35.573771 \approx 35.57 years.

In sum, the 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Notice that the "mean age of an inmate on death row was 40.7 years in 2002", and this value is between the limits of the 95% confidence interval obtained. So, according to the random sample under study, it seems that this mean age has not changed.

7 0
3 years ago
6a^2-[-5a-(9a^2-3a)]-[8+(-19a-8)]
Mamont248 [21]
The answer is 15a^2+21a
5 0
3 years ago
Other questions:
  • In the figure, angle B measures 44°, angle A measures 62°, and angle E measures 50°.
    14·1 answer
  • Help me with thisss simplify : 6³/6⁶
    12·1 answer
  • a,park guide plans the swan boat rides for 40 people.Each boat can carry 6 people at a time. What is the best way to interpret t
    13·2 answers
  • Resources Complete each of the definitions with the appropriate phrase. Precision means that measurements are close to measureme
    13·1 answer
  • Emerson has an associate degree. Based on the bar chart below, how will his employment opportunities change from 2008-2018?
    14·1 answer
  • Y is between points J and A. JA=17 and YA=3. What is JY?
    12·2 answers
  • Solve using zero product property: 2x^2-5x-6=0
    9·1 answer
  • Which is smaller 7/8 or 3/4
    5·2 answers
  • 48x + 6 factored is 6 (8x + 1)<br> True<br> False
    15·2 answers
  • A sports news station wanted to know whether people who live in the North or the South are bigger sports fans. For its study, 17
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!