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3 years ago

What is the volume of a sphere with a radius of 4 cm?

Mathematics

2 answers:

Margaret [11]3 years ago

8 0

Answer:

Option D - 267.95 cm³

Step-by-step explanation:

Given : Radius of sphere = 4 cm

To find : Volume of the sphere

Formula to find volume of sphere= $\frac{4}{3}\pi r^{3}unit^3$

Now, we put radius(r)=4 and $\pi= 3.14$ in the formula

Volume of sphere= $\frac{4}{3}\pi r^{3}$

= $\frac{4}{3}\times3.14\times4^3$

= $\frac{4}{3}\times3.14\times64$

= $\frac{803.84}{3}$

= $267.946cm^3$

= $267.95cm^3$

Therefore, option D is correct

volume of sphere= $267.95cm^3$

Masja [62]3 years ago

6 0

V ≈268.08cm³

here is your answer

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Answer:

Answer is 33. 15

Step-by-step explanation:

So I added the number of days 18 months could have then multiplied by 6.5%

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2 years ago

CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte

rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

$\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt$

By definition of absolute value,

$|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)$

Over this particular integration interval,

• sin(t ) ≥ 0 for 1 ≤ t < π, and

• sin(t ) < 0 for π < t ≤ 5

so you end up splitting the integral at t = π as

$\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt$

Now compute the distance:

$\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5$

$\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))$

$\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82$

making B the correct answer.

7 0

2 years ago

This year Reuben watched 80 movies. He thought that 68 of them were very good. Of the movies he watched, what percentage did he

Leya [2.2K]

Answer:

He thought that 85% of them were very good.

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2 years ago

Read 2 more answers

3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +

klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

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3 years ago

8 3/5 - ( 1 1/2 x 3 1/5 )

Ber [7]

8 3/5 - (1 1/2* 3 1/5)
= 43/5 - 24/5
= 19/5
= 3 4/5

Final answer: 3 4/5~

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2 years ago