Answer: the answer has to be a because the other ones are not even close
Step-by-step explanation:
If you do the distance formula you get 13 as the answer.
Actually, when you know 2 sides and an included angle, you use the Law of Cosines. (and we don't know if theta is an included angle).
Solving for side c
c^2 = a^2 + b^2 -2ab * cos(C)
c^2 = 36 + 16 - 2*6*4 * cos(60)
c^2 = 52 -48*.5
c^2 = 28
c = 5.2915
Using the Law of Sines
side c / sin(C) = side b / sin (B)
5.2915 / sin(60) = 4 / sin (B)
sin(B) = sin(60) * 4 / 5.2915
sin(B) = 0.86603 * 4 / 5.2915
<span><span>sin(B) = 3.46412
</span>
/ 5.2915
</span>
<span><span><span>sin(B) = 0.6546571451
</span>
</span>
</span>
Angle B = 40.894 Degrees
sin (A) / side a = sin (B) / side b
sin (A) = 6 * sin (40.894) / 4
sin (A) = 6 * 0.65466 / 4
sin (A) = .98199
angle A = 79.109 Degrees
angle C = 60 Degrees
Answer:
The correct option is 4.
Step-by-step explanation:
Given information:
Bring lunch : 46 males, 254 females
Buy lunch : 176 males, 264 females
Total number of peoples is
Total number of males is
The probability of male is
Since probability of males is 0.3, therefore options A and C are incorrect.
Total number of persons who buys lunch is
The probability of persons who buys lunch is
We need to find the probability of P(male | buys lunch).
According to the conditional probability, we get
P(male | buys lunch)
P(male | buys lunch)
P(male | buys lunch)
Therefore the correct option is 4.
Answer:
KL = 50
Step-by-step explanation:
∆JML is similar to ∆JNL. it follows that:
[tex] \frac{JM}{JN} = \frac{JL}{JK} [\tex]
JM = 4 + 20 = 24
JN = 4
JL = 10 + KL
JK = 10
Plug in the values
[tex] \frac{24}{4} = \frac{10 + KL}{10} [\tex]
[tex] 6 = \frac{10 + KL}{10} [\tex]
Multiply both sides by 10
[tex] 6*10 = \frac{10 + KL}{10}*10 [\tex]
[tex] 60 = 10 + KL [\tex]
Subtract 10 from each side
[tex] 60 - 10 = KL [\tex]
[tex] 50 = KL [\tex]
KL = 50
