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3 years ago

What name should be used for the ionic compound KOH?

Chemistry

1 answer:

vivado [14]3 years ago

5 0

Answer:

Potassium hydroxide

Explanation:

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Convert each of the measurements given to the new unit stated using the factor label method (dimensional analysis). Show all wor

jeka94

26 cm -0.26 m

4 hr - 240 min

3.25 km -3250 m

5 ft -60 inches

8 0

3 years ago

5. How many moles of gas are in a 7.5 L container, at 1 atm of pressure, at 100 degrees

loris [4]

Answer:

Ok; just use PV=nRT solve for n.

Explanation:

7 0

3 years ago

Find the final product for: Li + Br and show work.

miskamm [114]

Lithium is atomic number 3, so it has valency 1

While, Bromine is atomic number 35, and has valency 1

Lithium has an extra electron while Bromine need an electron, since they both need and have one electron, the form

LiBr (Lithium Bromide) where Li is +ve charged and Br is -ve charged

Happy to help :)

7 0

3 years ago

A balloon originally had a volume of 4.39 L at 44C and a pressure of 729 torr to what temperature must the balloon be cooled

VMariaS [17]

The new temperature : 11.56 °C

<h3>Further explanation </h3>

Boyle's law and Gay Lussac's law

$\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}$

P1 = initial gas pressure (N/m² or Pa)

V1 = initial gas volume (m³)

P2 = final gas pressure

V2 = final gas volume

T1 = initial gas temperature (K)

T2 = final gas temperature

V₁=4.39 L

T₁=44+273=317 K

P₁ = 729 torr = 0,959211 atm

V₂=3.78 L

P₂= 1 atm

$\tt \dfrac{0.959211\times 4.39}{317}=\dfrac{1\times 3.78}{T_2}\\\\T_2=\dfrac{1\times 3.78\times 317}{0.959211\times 4.39}\\\\T_2=284.559~K=11.56~C$

3 0

3 years ago

Express the rate of the reaction in terms of the change in concentration of each of the reactants and products.

weeeeeb [17]

Answer:

c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$2HBr(g)\rightarrow H_2(g)+Br_2(g)$

Thus, the rate is given as:

$rate=-\frac{1}{2} \frac{\Delta [HBr]}{\Delta t}=\frac{\Delta [Br_2]}{\Delta t} =\frac{\Delta [H_2]}{\Delta t}$

It is necessary to remember that each concentration to time interval is divided into the stoichiometric coefficient, that is why HBr has a 1/2. Moreover, the concentration HBr is negative since it is a reactant and it has a negative rate due to its consumption.

Therefore, the answer is:

c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt

Best regards.

4 0

3 years ago