Answer:
11.65 g
Explanation:
Amount of NaCl  = 15.0 grams
amount of H₂SO₄ = Excess
mass of hydrochloric acid (HCl) = ?
Solution:
To solve this problem first we will look for the reaction that NaCl react with  H₂SO₄
Reaction:
           2NaCl + H₂SO₄ --------> 2 HCl + Na₂SO₄
As the  H₂SO₄ is in excess so the amount of hydrochloric acid (HCl) depends on the amount of NaCl as it its act as limiting reactant.
Now if we look at the reaction
           2NaCl + H₂SO₄ --------> 2HCl + Na₂SO₄
            1 mol                              2 mol   
Now convert moles to mass
Then
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol 
Molar mass of HCl = 1 + 35.5 = 36.5 g/mol
So,
              2NaCl           +      H₂SO₄     -------->       2HCl        +     Na₂SO₄
       2 mol (58.5 g/mol)                                    2 mol (36.5 g/mol)
               94 g                                                           73 g
So if we look at the reaction; 94 g of NaCl gives with 73 g of hydrochloric acid (HCl) in a this reaction, then how many grams of hydrochloric acid (HCl) will produce from 15.0 g of NaCl
For this apply unity formula
            94 g of NaCl  ≅ 73 g of HCl
            15.0 g of NaCl  ≅ X g of HCl
By Doing cross multiplication
            X g of HCl = 73 g x 15.0 g / 94 g
            X g of HCl = 11.65 g
11.65 g of hydrochloric acid (HCl) will produce by 15.0 g of NaCl