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jolli1 [7]
3 years ago
9

What is the mass, in grams, of 1.33 mol of water, H2O?

Chemistry
1 answer:
Len [333]3 years ago
8 0

Answer:

24.0g H2O

Explanation:

1.33 mol (18.016g/1 mol) = 24.0g H2O

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Which of the following concerning the effects of temperature and pressure on solubility is/are correct?
just olya [345]

Answer:

None of the options are correct.

Explanation:

1) when the temperature of the solution is increased the solubility of the gas in the liquid decreases , hence option 1 is incorrect.

2)The heat released by the dissolution of an ionic compound in water is heat of hydration of the compound and is independent of the initial temperature of the solution.

3) The solubility of a liquid in water is not affected significantly by the pressure changes in the system as gases only have a significant cahne in solubility with change in pressure.

5 0
3 years ago
A sample has a mass of 15 g and a volume of 3 mL calculate the density
zlopas [31]
Since density is mass/volume, the density is 5g/ml.
7 0
3 years ago
8. A student filled a graduated cylinder with water and read the meniscus at 25.8 mL. The student
fomenos

Answer:

<h2>30.2 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

volume = final volume of water - initial volume of water

From the question

volume = 35.9 ml - 25.8 ml = 10.1 mL

We have

mass = 2.99 × 10.1 = 30.199 g

We have the final answer as

<h3>30.2 g</h3>

Hope this helps you

5 0
3 years ago
Be sure to answer all parts. Consider the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g)ΔH = −198.2 kJ/mol How would the concentrations of S
andrew-mc [135]

Answer:

a)

[SO2]: The concentration increases

[O2]: The concentration increases.

[SO3]: The concentration decreases.

b)

[SO2]: The concentration decreases.

[O2]: The concentration decreases.

[SO3]: The concentration increases.

c)

[SO2]:There is no change.

[O2]: There is no change.

[SO3]: There is no change

Explanation:

For an exothermic reaction, increase in temperature decreases the concentration of products and increases the concentration of reactants since increase in temperature shifts the equilibrium position to the left hand side.

Increase in pressure and decrease in volume will shift the equilibrium position towards the right hand side which means more SO3 in the system.

Catalyst increases the rate of forward and reverse reaction simultaneously hence at equilibrium, the concentration of reactants and products remain unchanged.

4 0
3 years ago
Can someone help me to figure out them please
Ronch [10]
2)NCl3
4)N2O3
5)NH3
6)B2H2
7)K3P
8)OF2
9)Mg(NO3)2
10)Al2(CO3)3
5 0
3 years ago
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