INTERmolecular forces (such as dipoles and London dispersion forces).
The actually compound isn't changing (it's still H2O in solid or liquid form), so INTRAmolecular bonds aren't being affected. It's just the strength of attraction between separate molecules that is weakening.
Neutrons have no electrical charge.
(2.4 x 10 24) divided by (6 x 10 23)=
The empirical formula of the compound containing 0.64 g of copper, 0.32 g of sulphur and 0.64 g of oxygen is CuSO₄
From the question given above, the following data were obtained:
Mass of Cu = 0.64 g
Mass S = 0.32 g
Mass of O = 0.64 g
<h3>Empirical formula =? </h3>
The empirical formula of the compound can be obtained as follow:
Cu = 0.64 g
S= 0.32 g
O = 0.64 g
Divide by their molar mass
Cu = 0.64 / 63.5 = 0.01
S= 0.32 / 32 = 0.01
O = 0.64 / 16 = 0.04
Divide by the smallest
Cu = 0.01 / 0.01 = 1
S= 0.01 / 0.01 = 1
O = 0.04 / 0.01 = 4
Therefore, the empirical formula of the compound is CuSO₄
Learn more: brainly.com/question/13086832
We solve for the number of mols of CO2 given its volume, assuming that it is an ideal gas.
n = PV / RT
Substituting,
n = (1 atm)(15.67 L) / (0.082 L.atm/mol.K)(273.15 K) = 0.7 moles
From the balanced chemical reaction above, we determine the number of O2 moles needed to produce 0.7 moles CO2.
0.7 moles CO2 x (3 moles O2/ 2 moles CO2) = 1.05 moles O2
Then, we multiply this value by 22.4 L/mol
1.05 moles O2 x (22.4 L / mol) = 23.52 L O2
Thus, the answer is the fourth choice.