Answer:
A. {(0, 3), (1, 6), (2, 9)}
Step-by-step explanation:
All you have to do is substitute them
A.
y − 3 = 3x
3 - 3 = 3 (0)
0 = 0
y − 3 = 3x
6 - 3 = 3 (1)
3 = 3
y - 3 = 3x
9 - 3 = 3 (2)
6 = 6
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B.
y - 3 = 3x
0 - 3 = 3(3)
-3 = 6
You can tell that this one can't be one of the answer which means that B wont be the answer, so you don't have to do anymore work for this one.
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C.
y - 3 = 3x
3 - 3 = 3(1)
0 = 3
This one can't be an answer either
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D.
y - 3 = 3x
1 - 3 = 3(1)
-2 = 3
And this one can't be an answer either
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This concludes, that A will be the answer here since all of the ordered pair can be x and y when you use the inputs and outputs that were given.
Hope this helped!
Three unknowns requires three equations to solve . . .
1) n + d + q = 30
2) d = 2n
3) (0.05)n + (0.10)d + (0.25)q = 5.50
* plug 2) into 1) and solve for q
n + 2n + q = 30
3n + q = 30
q = 30 - 3n
* now we have variables d and q expressed in terms of n, so we plug those equations into 3) and solve for n . . .
0.05n + 0.10(2n) + 0.25(30 - 3n) = 5.50
0.05n + 0.20n + 7.50 - 0.75n = 5.50
(0.05 + 0.20 - 0.75)n + 7.50 = 5.50
-0.50n + 7.50 = 5.50
-0.50n = 5.50 - 7.50
-0.50n = -2.00
n = -2.00/-0.50 = 4
d = 2n = 2(4) = 8
q = 30 - 3n = 30 - 3(4) = 30 - 12 = 18
The answer is . . .
n = 4 nickels
d = 8 dimes
q = 18 quarters
. . . for a total of (4 + 8 + 18) = 30 coins
. . . 8 dimes is twice 4 nickels
. . . $0.05(4) + $0.10(8) + $0.25(18) = $5.50
1) 2 -7-19
2x=19+7
2x=26
X=13
2) +5=12
-x/3+5=12
-x+15=36
-x=36-15
-x=21
X=-21
3)x-5=4
3x-20=16
3x=16+20
3x=36
X=12
Answer: Php 107.55
Step-by-step explanation:
From the question, Marlon saves Php 4.50 on Monday, Php 7.25 on Tuesday, Php 5.55 on Wednesday, Php 3.95 on Thursday, and Php 8.15 on Friday . The Total amount saved will be:
= 4.50 + 7.25 + 5.55 + 3.95 + 8.15
= 29.40
Amount saved for 3 weeks will be:
= 29.40 × 3
= 88.20
Since the lunch box he wants to buy costs Php 195.75 and he has saved Php 88.20. The remaining amount will be:
= 195.75 - 88.20
= 107.55