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harkovskaia [24]
2 years ago
5

Evaluate log25+log8 _log2​

Mathematics
1 answer:
Lemur [1.5K]2 years ago
7 0

Step-by-step explanation:

log 25 + log 8 = log (25 × 8) = log 200

log 200 - log 2 = log (200 ÷ 2) = log 100

logarithm base 10 of 100 is 2.

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If i run a 5.31 second in 40 meter what would i run in a 40 yard dash
-Dominant- [34]

Answer:

im not sure , sorry... i wish i could have helped

5 0
3 years ago
Cindi is planting a rectangular flower bed with 40 orange flower and 28 yellow flowers. She wants to plant them so that each row
Vilka [71]

Answer: 17 rows, 7 of yellow flowers and 10 of orange flowers.

Step-by-step explanation:

We have 40 orange flowers

we have 28 yellow flowers.

The total number of flowers is 40 + 28= 68

Now, we want to find the maximal comon factor between 28 and 40 (that will be the number of flowers in each row)

for this, we took the smallest number and find its factors, and then we see if those factors are also of the greater number.

28/1 = 28 ----> 40/28 is not integer, so 28 is not a factor of 40.

28/2 = 14 ----> 40/14 is not integer, so 14 is not a factor of 40.

28/3 is not integer.

28/4 = 7 ----> 40/7 is not integer, so 7 is not a factor of 40.

28/5 is not integer.

28/6 is not integer.

28/7 = 4, 40/4 = 10, so 4 is a factor of both 28 and 40.

Then the maximum number of flowers that we can put in each row is 4.

this means that we have:

28/4 = 7 rows of yellow flowers (with 4 flowers each)

40/4 = 10 rows of orange flowers (with 4 flowers each)

a total of 17 rows.

3 0
3 years ago
............................
Vika [28.1K]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
The function f(x)=-(x-3)^2 +9 can be used to represent the area of a rectangle with the perimeter of 12 units, as a function of
Ivenika [448]

Maximum area of the rectangle is 9cm^{2}

<u>Explanation:</u>

<u></u>

Considering the dimensions to be in cm

f(x) = -(x-3)^{2} +9\\f(x) = -(x^{2} +9 - 6x)+9\\f(x) = -x^{2} +6x\\f'(x) = -2x+6\\-2x+6 = 0\\2x=6\\x=3cm\\\\

Putting the value of x = 3

Perimeter = 2(x+b)\\12 = 2(3+b)\\6 = 3+b\\b= 3cm

Area of rectangle = x X b\\                              = 3 X 3\\                              = 9cm^{2}

Therefore, maximum area of the rectangle is 9cm^{2}

7 0
3 years ago
Evaluate the function when x=−2, 0, and 5. g(x)=3x−2
kipiarov [429]
I hope this helps....

x=-2
g(-2)= 3(-2)-2
= -6-2
g(-2)= -8

x=0
g(0)= 3(0)-2
=-2

x=5
g(5)=3(5)-2
g(5)=13
5 0
3 years ago
Read 2 more answers
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