The answer to this is C I-beam
Answer:
int calculate_cost(int quantity) {
double cost = 0;
if (quantity <= 20)
cost = quantity * 23.45;
else if (quantity >= 21 && quantity <= 100)
cost = quantity * 21.11;
else if (quantity > 100)
cost = quantity * 18.75;
return cost;
}
Explanation:
Create a function called calculate_cost that takes one parameter, quantity
Initialize the cost as 0
Check the quantity using if else structure. Depending on the quantity passed, calculate the cost. For example, if the quantity is 10, the cost will be $234.5
Return the cost
Answer:
Like an actual video game or the one where you would play during recess then get in trouble when someone got hurt
Explanation:
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
Act on your emotions not your first thought of something wrong