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g100num [7]
3 years ago
10

a chef bought 3 bags of beans. Each bag contains 1 2/5 kilogram of beans. How many kilograms of beans did she buy?

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0

Answer:

4.2 kilograms

Step-by-step explanation:

morpeh [17]3 years ago
4 0

Answer:

1.2

Step-by-step explanation:

He bought= 3 bags

Kg of one bag=1⅖

3×1⅖=1.2 kg

She bought 1.2 kg of beans..

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Juan has x apples and 8 oranges. How many fruits does he have? Give your answer in terms of x
zubka84 [21]
X apples and 8 oranges = x+8

The answer is x+8.

Hope this helped☺☺
3 0
4 years ago
Is this graph continuous at x=1?
drek231 [11]

Answer:

Step-by-step explanation:

By my definition, no. There's a continuity up to and including just before 1 approaching from the left, and there's a continuity just after 1 going to the right. But 1 itself has a special definition h(x) = 4 when x = 1 and that makes it discontinuous.

8 0
3 years ago
The numbers in this chart represent the weights in kilograms of five members of a middle school boys’ baseball team.
ioda

The record that represents an outlier in this data set is John's weight.

<h3>What is an outlier?</h3>

An outlier is a data point that differs significantly from other observations.

In other words, an outlier is a value or point that differs substantially from the rest of the data.

Therefore, the record that represents an outlier in this data set is  John's weight. This is because it is on the

learn more on outliers here: brainly.com/question/12978982

#SPJ1

7 0
2 years ago
What is the maximum value of the feasible regions if P = 120x + 100y
harkovskaia [24]

Answer:

The maximum value of the feasible regions is P=500

Step-by-step explanation:

we know that

To find out the maximum value of the feasible regions, substitute the value of x and the value of y of each region in the objective function P and then compare the results

we have

P=120x+100y

Region 1 (0,5)

For x=0, y=5

substitute

P=120(0)+100(5)=500

Region 2 (0,4)

For x=0, y=4

substitute

P=120(0)+100(4)=400

Region 3 (4,0)

For x=4, y=0

substitute

P=120(4)+100(0)=480

Region 4 (3,0)

For x=3, y=0

substitute

P=120(3)+100(0)=360

Compare

The maximum value of the feasible regions is P=500

5 0
3 years ago
Solve the system using elimination.<br> 3x + 5y = 55<br> 5x + 4y = 57
Eva8 [605]

Answer:

x=5, y=8. (5, 8).

Step-by-step explanation:

3x+5y=55

5x+4y=57

---------------

5(3x+5y)=5(55)

-3(5x+4y)=-3(57)

-------------------------

15x+25y=275

-15x-12y=-171

---------------------

13y=104

y=104/13

y=8

3x+5(8)=55

3x+40=55

3x=55-40

3x=15

x=15/3

x=5

5 0
3 years ago
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